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iVinArrow [24]
3 years ago
5

ITUS PIOLO

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
3 0

Answer:

\boxed{ \tt{187.5g}}

Explanation:

let \: the  \:  o_m \: be  \to \:  1500g\\ let \: the  \: h_l: be \to  20s\\ for \: every \: 20s : o_m \: is \: reduced\: by \:  \frac{1}{2}  \to \\ hence \: after \: 1min \: (60s = three \: 20s) \\ hence \to \\ after \: the \: first \: 20s \: o_m =  \frac{1500}{2}  = 750g\\ after \: the \: second \: 20s \: o_m =  \frac{750}{2}  = 375g \\ after \: the \: third \: 20s \: o_m =  \frac{375}{2}  = 187.5g \\ hence \: after \: a \: minute \: the \: orgial \: sample :  \\  \boxed{ \tt{o_m : 1500g \: will \: be  \: to \: 187.5g}}

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