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laila [671]
3 years ago
10

For the reaction...

Chemistry
1 answer:
MAVERICK [17]3 years ago
7 0

Answer:

A: Shift to the left

Explanation:

The reaction would try to use up the added heat by making more H 2 and Cl 2.

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An aqueous solution of cesium chloride is prepared by dissolving 52.3 g cesium chloride in 60.0g of water at 25°C. The volume of
LekaFEV [45]

Given data:

Mass of cesium chloride CsCl (m) = 52.3 g

Mass of water (mh2O)= 60.0 g

Volume of the solution (V) = 63.3 ml

Step 1: Calculate the number of moles of CsCl

Molar mass of CsCl = 168.36 g/mol

Mass of CsCl = 52.3 g

# moles = mass/molar mass = 52.3 g/168.36 g.mol-1 = 0.3106 moles

Step 2: Volume of solution in Liters

1000 ml = 1 liter

therefore, 63.3 ml corresponds to : 63.3 ml * 1 L/1000 ml = 0.0633 L

Step 3: Calculate molarity of CsCl

Molarity = moles of CsCl/volume of solution

            = 0.3106 moles/0.0633 L = 4.91 moles/L

Molarity = 4.91 M


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How many more atoms are there in 48g of C compared with 48.6g of Mg? Explain your answer.
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