Answer:
![K = \frac {[Cr_{2}O_{7}^{2-}]}{[CrO_{4}^{2-}]^{2} \cdot [H_{3}O^{+}]^{2}}](https://tex.z-dn.net/?f=%20K%20%3D%20%5Cfrac%20%7B%5BCr_%7B2%7DO_%7B7%7D%5E%7B2-%7D%5D%7D%7B%5BCrO_%7B4%7D%5E%7B2-%7D%5D%5E%7B2%7D%20%5Ccdot%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%5E%7B2%7D%7D%20)
Explanation:
The equilibrium constant for a given reversible aqueous reaction is defined by the product ratio of the concentrations between the products and reactants:
aA + bB ⇄ cC + dD
![K = \frac {[products]^{p}}{[reactants]^{r}} = \frac {[C]^{c} \cdot [D]^{d}}{[A]^{a} \cdot [B]^{b}}](https://tex.z-dn.net/?f=%20K%20%3D%20%5Cfrac%20%7B%5Bproducts%5D%5E%7Bp%7D%7D%7B%5Breactants%5D%5E%7Br%7D%7D%20%3D%20%5Cfrac%20%7B%5BC%5D%5E%7Bc%7D%20%5Ccdot%20%5BD%5D%5E%7Bd%7D%7D%7B%5BA%5D%5E%7Ba%7D%20%5Ccdot%20%5BB%5D%5E%7Bb%7D%7D%20)
<em>where K: is the equilibrium constant, [C] and [D]: are the product concentrations, [A] and [B]: are the reactant concentrations and a,b,c,d: are the stoichiometric coefficients from the reaction. </em>
Therefore, based on the definition the equilibrium constant of our reaction is:
2CrO₄²⁻(aq) + 2H₃O⁺(aq) ⇄ Cr₂O₇²⁻(aq) + 3H₂O(l)
Generally, the water concentration is omitted from the expressions.
I hope it helps you!
8.03 solutions report is described below.
Explanation:
8.03 Solutions Lab Report
In this laboratory activity, you will investigate how temperature, agitation, particle size, and dilution affect the taste of a drink. Fill in each section of this lab report and submit it and your pre-lab answers to your instructor for grading.
Pre-lab Questions:
In this lab, you will make fruit drinks with powdered drink mix. Complete the pre-lab questions to get the values you need for your drink solutions.
Calculate the molar mass of powered fruit drink mix, made from sucrose (C12H22O11).
Using stoichiometry, determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL.
Answer: 2.5 feet is already in 2 sig figs, in inches it would be 30. (30 including the deciaml) and in cm it would be 76
Explanation:
NaH(s)+ H2O (l)=>NaOH(aq)+H2(g)
You want to calculate the mass of NaH, I assume. Otherwise, the question isn't clear. It simply says calculate the mass(??)
So, calculate the moles of H2 gas that satisfy the conditions of 982 ml at 28ºC and 765 torr. But you must subtract the vapor pressure of water at 28º to get the actual pressure of the H2 gas. So, the actual conditions are 982 ml (0.982 L) and 301 K and 765-28 = 737 torr.
PV = nRT
n = PV/RT = (737 torr)(0.982 L)/(62.4 L-torr/Kmol)(301 K)
n = 0.0385 moles H2
moles NaH needed = 0.0385 moles H2 x 1 mole NaH/mole H2 = 0.0385 moles NaH required
mass of NaH needed = 0.0385 moles x 24 g/mole = 0.925 g NaH
Brainliest Please :)
