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lilavasa [31]
2 years ago
13

Explain why atoms would gain or lose electrons in order to resemble the elements in the particular group you named above. Consid

er what you learned about elements in that group.
Chemistry
1 answer:
posledela2 years ago
6 0

Answer:

<em>The number of electrons in the outermost shell of an element is represented in the periodic table as the group number that element is situated in. ... the number of electrons in all shells of an element is represented in the periodic table as the element's atomic number.</em>

Explanation:

<em>thatdummyemily </em>

<em>hope this helps srry if it doesn't tho, but if it does help can u plz mark me brainlist</em>

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A metallurgist is making an alloy that consists of 325 grams of chromium (Cr) and 2.5 kg of iron (Fe). Find the total mass of th
Darya [45]

Answer:- Mass of the alloy is 2.8 kg.

Solution:- Mass of Cr in the alloy is 325 g and mass of Fe in the alloy is 2.5 kg. Mass of alloy would be the sum of masses of constituent metals.

Masses of the metals are not in the same units. So, we need to make the units equal. The want answer in kg so let's convert mass of Cr from g to kg.

Since, 1000 g = 1 kg

So, 325g\frac{1kg}{1000g}

= 0.325 kg

Mass of alloy = mass of Cr + mass of Fe

mass of alloy = 0.325 kg + 2.5 kg = 2.825 kg

If we consider significant figures then as per the rules, the answer should not have more than one decimal place.

So, 2.825 kg is round off to 2.8 kg and hence the mass of the alloy is 2.8 kg.

5 0
3 years ago
Which of the following is a true statement about odors?
Novay_Z [31]
Pretty sure its all of the above since all of them are true
5 0
2 years ago
R is the midpoint of FG.<br><br> FR = 26 find RG
vichka [17]

Answer:

52

Explanation:

This is because if R is the midpoint of FRG, FR is half of FRG, so basically all you do it multiply by 2 to get the FRG

7 0
3 years ago
What 2 properties make capillary action possible
Natali5045456 [20]
Cohesion and adhesion
7 0
3 years ago
under certain water​ conditions, the free chlorine​ (hypochlorous acid,​ hocl) in a swimming pool decomposes according to the la
ivolga24 [154]

Answer:

1.7 ppm

Explanation:

Original amount N' = 2.6 ppm

time to testing t = 24 hr

final amount N = 2.1 ppm

Using exponential inhibited decay, we have

N = N'e^(-kt)

Where

N is the new reading

N' is the original reading

t is the decay time

k is the decay constant

Substituting, we have

2.1 = 2.6 x e^(-k x 24)

2.1 = 2.6 x e^(-24k)

0.808 = e^(-24k)

We take the natural log of both sides of the equation

Ln 0.808 = Ln (e^(-24k))

-0.213 = - 24k

K = 0.213/24 = 0.00886

After 48 hrs, the reading of free chlorine will be

N = 2.6 x e^(-0.00886 x 48)

N = 2.6 x e^(-0.425)

N = 2.6 x 0.654

N = 1.7 ppm

5 0
3 years ago
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