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Harrizon [31]
3 years ago
8

Which statement is true if CH = 6

Mathematics
1 answer:
Rashid [163]3 years ago
6 0
C) because it equals each other
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Keith_Richards [23]
D is the answer. hth.
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Identify the variables, objective functions, and constraints
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What does it constraints?
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3 years ago
“Solve the system using elimination” im not good at math so can someone help me
iris [78.8K]

Answer:

No solutions

Step-by-step explanation:

i did this via substitution so i hope it isn't a problem

3x+y=4

6x+2y=−4

Step: Solve 3x+y=4for y:

3x+y+−3x=4+−3x(Add -3x to both sides)

y=−3x+4

Step: Substitute−3x+4foryin6x+2y=−4:

6x+2y=−4

6x+2(−3x+4)=−4

8=−4(Simplify both sides of the equation)

8+−8=−4+−8(Add -8 to both sides)

0=−12

so there are no solutions

hope this helps!!

8 0
3 years ago
Please help! <br>Factor f(x)=x^4-x^3-7x^2+13x-6 completely. Then sketch the graph
stich3 [128]

For the complex roots I got 1,2,-3

6 0
3 years ago
How many permutations are there of the letters in the words (a) TRISKAIDEKAPHOBIA (fear of the number 13)? (b) FLOCCINAUCINIHILI
zubka84 [21]

Answer: Hello!

Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)

We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.

The total number of permutations is the product of the number of options that you have for each letter, this is:

17*16*15*14*....*3*2*1 = 17! = 3.6e+14

(b) FLOCCINAUCINIHILIPILIFICATION now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is

30! = 2.65e+32

(c) PNEUMONOULTRAMICROSCOPICSILICOVOLCANOCONIOSIS: now there are 47 letters.

then P = 47! = 2.59e+59

(d) DERMATOGLYPHICS: here are 18 letters, then:

p = 18! = 6.4e+15

6 0
3 years ago
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