First differences are 2, 4, 8, 16, which is a geometric sequence. The parent function is not linear (constant first difference) or quadratic (first difference increases by the same amount from one to the next). When the first differences are a geometric sequence, the underlying sequence is a geometric (exponential) sequence.
1st blank: exponential
Translation up adds a constant to each of the f(x) values.
2nd blank: f(x)
3rd blank: increased by 5<span>
For the last blank, you're looking for an (x, f(x)) pair that is translated to (x, f(x)+5).
4th blank: </span><span>(2, 16)</span>
Step-by-step explanation:
the scanned description is very hard to understand.
so I think what happened :
16x² - 9 = 16
then the first error :
sqrt(16x²) - sqrt(9) = sqrt(16)
that is wrong, as you cannot split a + or - operation inside a sqrt function into + or - separate sqrt results of the parts.
so, correctly, the only possible transformation involving sqrt for both sides :
sqrt(16x² - 9) = sqrt(16)
but it would be even easier to clean up the various constant numbers with each other.
so,
16x² - 9 = 16
16x² = 25
and now we trashes the square root
sqrt(16x²) = sqrt(25)
4x = 5
x = 5/4 or x = -5/4
and I cannot see or understand for my life what the second equation was, as Daniel did something wrong, so I cannot deduct the original equation out of a supposedly wrong
y³ - 1 = 7
Answer: A) .1587
Step-by-step explanation:
Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.
i.e. 
and 
Let x denotes the amount of soda in any can.
Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.
Then, the probability that a randomly selected can will need to go through the mentioned process = probability that a randomly selected can has more than 12.50 ounces of soda poured into it =
![P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587](https://tex.z-dn.net/?f=P%28x%3E12.50%29%3D1-P%28x%5Cleq12.50%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B12.50-12.30%7D%7B0.20%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1%29%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.8413%5C%20%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%5C%5C%5C%3D0.1587)
Hence, the required probability= A) 0.1587
Answer:
I can't answer the whole question but the first one is 7 x 9, or 63 squares. And say you chose a square that is 4 x 3 so that would be the area of the tile you chose. Im sorry I couldn't answer the whole thing but I hope that makes since of what I did, if not please ask questions.
Step-by-step explanation:
