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3 years ago

7

WILL MARK BRAINLIST. The dot plot below shows 4 data points with a mean of 6. A dot plot going from 1 to 10. 1 dot is above 2, 6

, 7, and 9. What is the absolute deviation at 2? –8 –4 4 8

2 answers:

loris [4]3 years ago

6 0

Answer:

C. 4

Step-by-step explanation:

Colt1911 [192]3 years ago

5 0

Answer:

C hope this helps <3

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The number of subscribers to a streaming video service doubles each week.

Ilya [14]

Answer:

Step-by-step explanation:

This is an exponential equation that is solved by taking the natural log of both sides. The equation is

$f(x)=2^x$

If we are looking for x when f(x) = 64, then

$64=2^x$

Take the natural log of both sides:

$ln(64)=ln(2^x)$

The rules of logs allows us to bring the x down in front:

$ln(64)=xln(2)$

Divide both sides by ln(2) to get:

$\frac{ln(64)}{ln(2)}=x$

Do this on your calculator to get that x = 6.

You could also have just gone right to your calculator and started raising 2 to consecutive powers starting at like 3 or 4 to eventually get that 2 to the 6th power is equal to 64, but for the basics of solving log equations, you need to know how to do this.

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3 years ago

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A grapefruit is 8% heavier than an orange, and an apple is 10% lighter than the

patriot [66]

Grapefruit=108

Orange=100

Apple=90

a) (108-90)/90*100 = 18/90*100=20%

b) (108-90)/108= 18/108*100=16 2/3%

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3 years ago

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Conceptual Set 1. The same researcher wants to then compare the final (time 2) levels of anger in this experimental group to a c

Mazyrski [523]

Answer:

I

Step-by-step explanation:

Because independent sample t-tests compare two completely different groups in a sample, which is what the researcher is attempting to do.

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What is the value of q in the equation 59 - 10 = 75?

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Answer: q=26

Step-by-step explanation:

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2 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago