Answer:
Never pour water into acid but acid into water
Explanation:
If water is poured into extremely concentrated acid/bases, the rate of volatility and exothermic reaction is too rapid and might cause a chemical eruption, leading to acid burns.
Safety precautions hence dictate the reverse is practiced.
I believe this is a clear answer.
This is an incomplete question, here is a complete question.
The conversion of cyclopropane to propene occurs with a first-order rate constant of 2.42 × 10⁻² hr⁻¹. How long will it take for the concentration of cyclopropane to decrease from an initial concentration 0.080 mol/L to 0.053 mol/L?
Answer : The time taken will be, 17.0 hr
Explanation :
Expression for rate law for first order kinetics is given by:
![t=\frac{2.303}{k}\log\frac{a}{a-x}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7Bk%7D%5Clog%5Cfrac%7Ba%7D%7Ba-x%7D)
where,
k = rate constant = ![2.42\times 10^{-2}\text{ hr}^{-1}](https://tex.z-dn.net/?f=2.42%5Ctimes%2010%5E%7B-2%7D%5Ctext%7B%20hr%7D%5E%7B-1%7D)
t = time passed by the sample = ?
a = initial concentration of the reactant = 0.080 M
a - x = concentration left = 0.053 M
Now put all the given values in above equation, we get
![t=\frac{2.303}{2.42\times 10^{-2}}\log\frac{0.080}{0.053}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7B2.42%5Ctimes%2010%5E%7B-2%7D%7D%5Clog%5Cfrac%7B0.080%7D%7B0.053%7D)
![t=17.0\text{ hr}](https://tex.z-dn.net/?f=t%3D17.0%5Ctext%7B%20hr%7D)
Therefore, the time taken will be, 17.0 hr
Etaphase is a stage during the process of cell division (mitosis or meiosis). Usually, individual chromosomes cannot be observed in the cell nucleus. However, during metaphase of mitosis or meiosis the chromosomes condense and become distinguishable as they align in the center of the dividing cell.
The statement which is true about the reactivity of element with 1S²2S²2P⁶3S¹ is
it is reactive because it has to lose one electron to have a full outermost energy level.
<u><em>Explanation</em></u>
- <u><em> </em></u>Element with 1S²2S²2P⁶3S¹ electron configuration is a sodium metal.
- sodium has one electron in the outermost energy level.
- for sodium to have a full outermost energy level ( 8 electrons) it loses the 1 electron in 3S¹ to form a positively charged ion. (Na⁺)
Answer:
d. P2O5.
Explanation:
We find the ratio of the atoms by dividing the percentages by the relative atomic masses:
P : 43.6 / 30.974 = 1.4076
O: 56.4 / 15.999 = 3.5252
1.4076 : 3.5252
= 1 : 2.5
= 2:5.
So the answer is P2O5.