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NARA [144]
3 years ago
5

Science 6th grade please help me :)

Chemistry
2 answers:
trapecia [35]3 years ago
8 0

the correct one is letter D.

Gnom [1K]3 years ago
6 0
I’m pretty sure the answer is D :)
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The activation energy for a(n) _____ is quite large and usually takes extra energy from the environment, it is normally not a na
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Answer:

The activation energy for an endothermic reaction is quite large and usually takes extra energy from the environment, it is normally not a natural spontaneous process.

Explanation:

  • Endothermic reactions require absorbing energy of the surrounding mainly in the form of heat.
  • Chemical energy needs energy input to break the bonds.
  • Examples of endothermic reactions: Photosynthesis , melting of ice , and evaporating liquid water.
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Element
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helium

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The possible products of a double displacement reaction in aqueous solution are SrSO4 and NaCl. Which of these possible products
madam [21]

Answer:

SrSO4

Explanation:

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Since SrSO4 is a sulphate of a group two element (strontium) it will be the insoluble solid product of the double displacement reaction described in the question.

7 0
3 years ago
An element has three different isotopes. One has a mass of 35.00 amu; another has a mass of 36.00 amu; and another has a mass of
yulyashka [42]

Answer:

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8 0
2 years ago
Analysis of an athletes urine found the presence of a compound with a molar mass of 312 g/mol. How many moles of this compound a
rewona [7]
<h3>Answer:</h3>

= 5.79 × 10^19 molecules

<h3>Explanation:</h3>

The molar mass of the compound is 312 g/mol

Mass of the compound is 30.0 mg equivalent to 0.030 g (1 g = 1000 mg)

We are required to calculate the number of molecules present

We will use the following steps;

<h3>Step 1: Calculate the number of moles of the compound </h3>

Moles=\frac{mass}{molar mass}

Therefore;

Moles of the compound will be;

=\frac{0.030}{312g/mol}

      = 9.615 × 10⁻5 mole

<h3>Step 2: Calculate the number of molecules present </h3>

Using the Avogadro's constant, 6.022 × 10^23

1 mole of a compound contains 6.022 × 10^23  molecules

Therefore;

9.615 × 10⁻5 moles of the compound will have ;

= 9.615 × 10⁻5 moles × 6.022 × 10^23  molecules

= 5.79 × 10^19 molecules

Therefore the compound contains 5.79 × 10^19 molecules

5 0
3 years ago
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