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Kruka [31]
3 years ago
6

How can you demonstrate waves?​

Chemistry
1 answer:
Lady bird [3.3K]3 years ago
7 0
Shaking a phone cord, strumming a guitar string, playing a trumpet
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What does chemistry mean
alina1380 [7]

Answer:

<em>The branch of natural science that deals with the composition and constitution of substances and the changes that they undergo as a consequence of alternations in the constitution of their molecules is chemistry.</em>

Explanation:

7 0
3 years ago
How do Newton's laws of motion explain why it is important to keep the ice smooth on a hockey rink so that players
andriy [413]

Answer:

How do Newton's laws of motion explain why it is important to keep the ice smooth on a hockey rink so that players can pass a puck as quickly as possible? Smooth ice reduces the unbalanced forces that would slow the hockey puck. A skydiver falls toward the ground at a constant velocity.

Explanation:

3 0
3 years ago
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What’s number 1, 2, 3 <br> Major grade 6th grade
Maslowich

Answer:

1 is B

2 is A

3 is A

Explanation:

Hope you pass

8 0
2 years ago
Why are carbon and nitrogen essential for survival to all living organisms? A.
bagirrra123 [75]
Hello there.

<span>Why are carbon and nitrogen essential for survival to all living organisms?
</span>
<span>They are needed to release the energy stored in food.
</span>Therefore, The correct answer would be Option B.
3 0
3 years ago
Read 2 more answers
An unknown diprotic acid (H2A) requires 44.391 mL of 0.111 M NaOH to completely neutralize a 0.58 g sample. Calculate the approx
Anna [14]

Answer:

M=235.42g/mol

Explanation:

Hello!

In this case, given this is an acid-base neutralization and we are considering a diprotic acid, we can write the following mole-mole relationship:

2n_{acid}=n_{base}

It means that the moles of acid can be computed given the volume and concentration of NaOH:

n_{acid}=\frac{M_{base}V_{base}}{2} =\frac{0.044391L*0.111mol/L}{2} \\\\n_{acid}=2.46x10^{-4}mol

It means that the approximate molar mass of the acid is:

M=\frac{m_{acid}}{n_{acid}} \\\\M=\frac{m_{acid}}{n_{acid}} =\frac{0.58g}{2.46x10^{-3}mol}\\\\M=235.42g/mol

Best regards!

5 0
2 years ago
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