Answer:
10,071 years
Step-by-step explanation:
If 'a' is the fraction remaining, it satisfies the equation ...
a = (1/2)^(t/5750)
Solving for t, we get ...
log(a) = log(1/2)×t/5750
t = 5750×log(a)/log(1/2) ≈ -19,101.09×log(a) . . . years
__
If 70.3% is lost, then 1 -0.703 = 0.297 is the fraction remaining. The age is estimated to be ...
-19,101.09×log(0.297) ≈ 10,071 . . . years
The bones were about 10,071 years old.
38 tens would mean 10 x 38= 380
So 380 - 100 = 280
The answer is 1,000. Hope this helps!
We know that
perimeter rectangle A=2*[5+3]-----> 16 in
let
x------> length side rectangle B
y-------> width side rectangle B
so
x=6+y-------> equation 1
16=2[x+y]------> equation 2
<span>I substitute 1 in 2
</span>16=2*[6+y+y]-------> 16=2*[6+2y]-----> 16=12+4y-----> 4y=16-12
y=4/4--------> y=1 in
x=6+1---->x=7 in
the answer is
the dimensions of rectangle B are
length side is 7 in
width side is 1 in