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Svetach [21]
2 years ago
9

Plz solve fast! what is the answer of this quation.

Mathematics
1 answer:
Alex_Xolod [135]2 years ago
3 0
49 is the answer to ur question
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Why are asymptotes important in rational function graphs
leonid [27]

Answer:

when sketching the curves of functions.

Step-by-step explanation:

There is a wide range of graph that contain asymptotes and that includes rational functions, hyperbolic functions, tangent curves, and more. Asymptotes are important guides when sketching the curves of functions. This is why it’s important that we know the properties, general forms, and graphs of each of these asymptotes.

6 0
1 year ago
Find the sine r 13 12 5
Neporo4naja [7]

Answer:

9

Step-by-step explanation:

4 0
3 years ago
Quadrilateral abcd is inscribed in a circle with m∠a = (x)degrees, m∠b = (2x - 10)degrees, and m∠c = (3x)degree. what is m∠d?
Lynna [10]
Hello,

When you have a polygon inscribed in a circle, the opposite angles are supplementary.

So we can start by saying that A + C = 180. Or x + 3x = 180. This gives us a value of 45 for x.

If we input that in for angle B, we get: 2(25) - 10 = 80.

If angle B = 80, then angle D must be 100, because the angles are supplementary.

Good luck,
MrEQ
6 0
3 years ago
Follow the steps for dividing decimals. Then, round to two decimal places (hundredths).
zvonat [6]

Answer:

4.32

Step-by-step explanation:

The steps required are:

         4.322

1.476 )6.380

          5.904

          ____

          0.476

              0.4763

              0.4428

              _____

              0.0335

                  0.03358

                  0.02952

                  _____

                  0.00406

                     0.004060

                     0.002952

                     _____

                     0.0011080

Therefore, the answer is 4.32.

8 0
2 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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