Answer:
The particle’s velocity is -16.9 m/s.
Explanation:
Given that,
Initial velocity of particle in negative x direction= 4.91 m/s
Time = 12.9 s
Final velocity of particle in positive x direction= 7.12 m/s
Before 12.4 sec,
Velocity of particle in negative x direction= 5.32 m/s
We need to calculate the acceleration
Using equation of motion
Where, v = final velocity
u = initial velocity
t = time
Put the value into the equation
We need to calculate the initial speed of the particle
Using equation of motion again
Put the value into the formula
Hence, The particle’s velocity is -16.9 m/s.
Answer:
Explanation:
Given
Diameter(D)=21.5 cm
distance between plate=1.75 mm
and we know capacitance is
and we know charge is
Q=CV
and charge density (![\sigma [tex])[tex]=\frac{Q}{A}=\frac{\epsilon _0AV}{Ad}=\frac{\epsilon V}{d}](https://tex.z-dn.net/?f=%5Csigma%20%5Btex%5D%29%5Btex%5D%3D%5Cfrac%7BQ%7D%7BA%7D%3D%5Cfrac%7B%5Cepsilon%20_0AV%7D%7BAd%7D%3D%5Cfrac%7B%5Cepsilon%20V%7D%7Bd%7D)
Electric field(E)
Energy density
Energy desity
Energy desity![=\frac{1}{8\pi \cdot 9\times 10^9}\times \left [ \frac{12\times 10^3}{1.75}\right ]^2](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B8%5Cpi%20%5Ccdot%209%5Ctimes%2010%5E9%7D%5Ctimes%20%5Cleft%20%5B%20%5Cfrac%7B12%5Ctimes%2010%5E3%7D%7B1.75%7D%5Cright%20%5D%5E2)
Answer:
a. get warmer.
Explanation:
When the water vaporous reach the upper layer of the atmosphere they get a cooler air to which they loose their temperature and condense to form clouds as a the temperature of the air increases.
It may be noted that the water looses its high amount of latent heat of vaporization to condense into water this significantly increases the temperature of the air in contact.
Answer:
The new time period will be T.
Explanation:
The time period in terms of spring constant and mass is given by :
If mass and force constant is doubled, m' = 2m and k' = 2k
New time period is given by :
So, the new period will remains the same. Hence, the correct option is (C).
We can answer this problem using Ampere’s Law:
<span>Bh = μoNI </span>
Where:
B = Magnetic Field
h = coil length
<span>μo = permeability =4π*10^-7 T·m/A </span>
N = number of turns
I = current
It is given that B=0.0015T, I=1.0A, h=10 cm =
0.1m<span>
Use Ampere's law to find # turns:
Which can be rewritten as:
<span>N = Bh/μoI </span>
N = (0.0015)(0.1)/(4π*10^-7)(1.0)
N = 119.4
</span>
<span>Answer:
119.4 turns</span>
