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3 years ago

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A light spring obeys Hooke's law. The spring's unstretched length is 33.5 cm. One end of the spring is attached to the top of a

doorframe and a weight with mass 7.00 kg is hung from the other end. The final length of the spring is 42.0 cm. What if

1 answer:

ZanzabumX [31]3 years ago

4 0

Answer:

807.88N/m

Explanation:

<em>The question has some missing details in it, nevertheless, based on the given data we want to find the spring constant K</em>

Step one

given data

Unstretched length = 33.5 cm

Final length of the spring = 42.0 cm

Δx= 42-33.5

Δx=8.5cm to m= 0.085m

mass m= 7kg

The force on the spring

F=mg

F= 7*9.81

F=68.67N

Step two:

From Hooke's law, we can make k subject of formula and find the spring constant k, we have

F=kΔx---------1

make k subject of the formula

k=F/Δx

k= 68.67/ 0.085

k=807.88N/m

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Answer:

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