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castortr0y [4]
3 years ago
7

What type of machine is wire cutter pliers?

Physics
2 answers:
Ghella [55]3 years ago
5 0

The correct answer is compound machine.


Sonja [21]3 years ago
3 0
It seems that you have missed the necessary options for us to answer this question, but anyway, here is the answer. The type of machine that a wire cutter pliers is classified is a simple machine. When we say simple machine, this is the type of machine that is considered basic wherein you need to apply force for it to function. Hope this helps.
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Pls answer the 15a answer i cant understand it​
Maksim231197 [3]

Materials required for the experiment of limiting force borne by string:-

  1. String balance
  2. weights
  3. light strings
  4. weight hanger
  5. pan for spring balance
  6. Sand

Steps of procedure for for the experiment of limiting force borne by string:-

  1. First we have to tie a light string to the fixed support and then tie the other end with the weight hanger consists of weight.
  2. Add additional weight to the hanger again and again. And continue the same until the string is broken.
  3. Note down the weight (x) where the string is broken.
  4. Suspend spring balance to a support.
  5. Tie the light string at the end of the balance and at the other end suspend the pan for spring balance.
  6. Now place the weights (x-100 grams) in pan.
  7. Observe the reading in the spring balance.
  8. Add a small amount of sand in the pan by observing the readings.
  9. same is to be done till the string is broken.

Learn more about limiting force here:- brainly.com/question/11371672

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6 0
1 year ago
The 1 kg box is sliding along a frictionless surface. It collides with and sticks to the 2 kg box. Afterward, the speed of the t
Nina [5.8K]

Answer:

The speed of the boxes are 1 m/s.

Explanation:

Given that,

Mass of box = 1 kg

Mass of another box = 2 kg

Suppose 1 kg box moves with 3 m/s speed.

We need to calculate the speed of the boxes

Using formula of conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=(m_{1}+m_{2})v

Where, u = initial velocity

v = final velocity

Put the value into the formula

1\times3+2\times0=(1+2)v

v=\dfrac{3}{3}

v=1\ m/s

Hence, The speed of the boxes are 1 m/s.

4 0
3 years ago
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