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meriva
3 years ago
6

Convert- a) 42° to kelvin b) 56k to °C c) 37° to °F d) 32° to °C

Physics
2 answers:
ra1l [238]3 years ago
8 0

Answer:

A. 318.15

B.-217.15

C. 132.8

D. 0

Explanation:

K − 273.15 = °C/°F

°C/ °F + 273.15 = K

(°C × 9/5) + 32 = °F

(°F − 32) × 5/9 = 0°C

umka21 [38]3 years ago
7 0

Answer:

k is celcius/farhneit +273

c is 5/9 f-32

f is 9/5 (c+32)

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A substance has a volume of 4,000 cm and a mass that is 2,000 g. What is the density of the substance.
podryga [215]
Density is mass divided by volume making the answer 0.5 g/cm^3
5 0
3 years ago
How much kinetic energy does 2200kg car have if it is moving at 35m/s
Korolek [52]

Answer:1347500joules

Explanation:

Kinetic energy=(mass(velocity)^2)/2

Kinetic energy=(2200(35)^2)/2

Kinetic energy=(2200×1225)/2

Kinetic energy=2695000/2

Kinetic energy=1347500joules

5 0
4 years ago
In one experiment, you measured the potential difference across a resistor as a capacitor discharged through it. You then plotte
Xelga [282]

Answer:

Explanation:

For discharge of capacitor in RC circuit , the relation is as follows

V=V_0e^\frac{-t}{\lambda}

V is voltage across the capacitor , V₀ is maximum  voltage across capacitor  , λ is time constant and t is the time after which the voltage is recorded. During discharge this will also be voltage across resistance .

Taking log on both sides

lnV = lnV₀   -  \frac{t}{\lambda}

Given equation

[lnV] = - .027 t + 2.5

Comparing these equation

\frac{1}{\lambda} = .027

λ = 37 s

time constant = 37 sec.

5 0
3 years ago
45 joules were expended to move a box weighing 30 newtons. How many meters was it moved?
slava [35]

Answer:

1.5 meter is the answer

7 0
3 years ago
A toy plane is flying in a horizontal circle by being attached to a 0.75 meter string. The plane has a mass of 101.7 grams and m
nadezda [96]

Answer:

F = 2,894 N

Explanation:

For this exercise let's use Newton's second law

      F = m a

The acceleration is centripetal

     a = v² / r

Angular and linear variables are related.

     v = w r

Let's replace

     F = m w² r

The radius r and the length of the rope is related

    cos is = r / L

    r = L cos tea

Let's replace

    F = m w² L cos θ

Let's reduce the magnitudes to the SI system

     m = 101.7 g (1 kg / 1000g) = 0.1017 kg

      θ = 5 rev (2π rad / rev) = 31,416 rad

     w =  θ / t

     w = 31.416 / 5.1

     w = 6.16 rad / s

     F = 0.1017 6.16² 0.75 cos  θ

     F = 2,894 cos  θ

The maximum value of F is for  θ equal to zero

     F = 2,894 N

7 0
3 years ago
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