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kkurt [141]
3 years ago
5

HELP! What is Jacobson's conjecture?

Mathematics
1 answer:
Elden [556K]3 years ago
8 0
In abstract algebra, Jacobson's conjecture is an open problem in ring theory concerning the intersection of powers of the Jacobson radical of a Noetherian ring.
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You have an initial amount of $55 in a savings account and you deposit an equal amount into your account each week. After 6 week
bonufazy [111]
Given:
initial deposit = 45
total deposit = 105
w = weekly deposit
x = no. of weeks = 5 weeks
y = amount in dollars
45 + 5w = 105
45 + 5w = 105
5w  = 105 - 45
5w =  60
w = 60/5
w = $12 weekly deposit.

y = $45 + $12x  
<span>x = (y - 45)/12

</span>To check:
y = 45 + 12(5)
y = 45 + 60
y = 105 total deposit in 5 weeks

x = (105-45)/12
x = 60/12
x = 5 weeks

I hope this help
8 0
3 years ago
Read 2 more answers
79+65<br> leave change change
vampirchik [111]
144                      I believe 
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veronica howard
6 0
3 years ago
-2/3- (-3/4)<br><br> Simplify if needed <br> Brainliest <br><br> Also, 5/6+5/12
bazaltina [42]

Answer:

-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}

\frac{5}{6} + \frac{5}{12} = \frac{5}{3}

Step-by-step explanation:

Given

-\frac{2}{3} - (-\frac{3}{4})

Required

Solve:

-\frac{2}{3} - (-\frac{3}{4})

Open bracket

-\frac{2}{3} - (-\frac{3}{4}) = -\frac{2}{3} +\frac{3}{4}

Take LCM

-\frac{2}{3} - (-\frac{3}{4}) = \frac{-8+9}{12}

-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}

\frac{5}{6} + \frac{5}{12}

Take LCM

\frac{5}{6} + \frac{5}{12} = \frac{10+5}{12}

\frac{5}{6} + \frac{5}{12} = \frac{15}{12}

Divide by 3/3

\frac{5}{6} + \frac{5}{12} = \frac{5}{3}

4 0
3 years ago
Without using a calculator, order the following numbers from least to greatest . 5 sqrt(14) 4
Flura [38]

Answer:

.5, sqrt 14, 4

Step-by-step explanation:

.5, 3.7416, 4

8 0
2 years ago
A box-and-whisker plot. The number line goes from 0 to 9. The whiskers range from 0 to 7, indicated by A and E. The box ranges f
Sladkaya [172]

minimum value: 1

lower quartile: 3

median of the data: 6

upper quartile: 8

maximum value: 14

Sorry for the late answer, i hope this will help you in the future and everyone else who reads this.

6 0
3 years ago
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