All categories

3 years ago

HELP! What is Jacobson's conjecture?

1 answer:

8 0

In abstract algebra, Jacobson's conjecture is an open problem in ring theory concerning the intersection of powers of the Jacobson radical of a Noetherian ring.

You might be interested in

The graph of a line has a slope of 2 and passes through the point (–6, –5). What is the equation of the line in point-slope form

Stolb23 [73]

Answer:

it would be

B. y + 5 = 2(x + 6)

if there is a negative number and you are subtracting it turns positive

Step-by-step explanation:

7 0

3 years ago

Y=6x+5 is the equation. what is its gradient

Irina18 [472]

Gradient is synonymous to slope.

y = 6x + 5 is an example of a slope-intercept form of a straight-line equationl.

The slope-intercept equation is like this:

y = mx + b

where : m = slope ; b = "y-intercept"

y = 6x + 5

6 is the slope
5 is the y-intercept.

Since slope and gradient are synonymous, 6 is the gradient of the above equation.

8 0

3 years ago

Which expression is equivalent to

mojhsa [17]

First choice: m^32n^16

Hope this helps!

6 0

3 years ago

Read 2 more answers

Which of the following expressions represents the distance between-1/4 and 3/4

Shalnov [3]

Answer:

|-1/4 - 3/4|

Step-by-step explanation:

To get the distance, take the absolute value of the second point minus the first point

| 3/4 - - 1/4|

|3/4 + 1/4|

We can also take the absolute value of the first point minus the second point

|-1/4 - 3/4|

4 0

3 years ago

The number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the

liq [111]

Answer:

<u>Option B. 59%</u>

Explanation:

The function that represents the number of E.coli bacteria cells per 100 mL of water as the time t years elapses is:

$A(t)=136(1.123)^{4t}$

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function:

$rate=(1.123)^{4t}=(1.123)^4=1.590$

Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

8 0

4 years ago