The ? Is 3
As 4^3 = 64
4x4x4= 64
Answer:
C
Step-by-step explanation:
Answer:
(2,4)
Step-by-step explanation:
We have the system:
y=x+2
y=3x-2.
This is already setup for substitution.
I'm going to replace my first y with what the second y equals.
That is, I'm going to write 3x-2=x+2.
Time to solve the following for x:
3x-2=x+2
Subtract x on both sides:
2x-2= 2
Add 2 on both sides:
2x. = 4
Divide both sides by 2:
x. = 2
Now that we know x=2 and we have an equation that relates x to y: either y=x+2 or y=3x-2, doesn't matter which we use, we can find y.
So we y=x+2 with x=2 which means y=2+2=4.
So the solution, the intersection, is (2,4).
Answer:
x = -3, x = 0 is a extraneous solution
Step-by-step explanation:
Step 1: Cross-multiply
3x² = 4x² + 3x
Step 2: Isolate <em>x</em>'s
0 = x² + 3x
Step 3: Factor
0 = x(x + 3)
Step 4: Find roots
x = 0, -3
Step 5: Double check work
Plug in both to see if they both work. Only x = 0 should be extraneous. We now have our answer!
Answer:
HAHA thanks dude
Step-by-step explanation:
