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icang [17]
2 years ago
8

How many unique roots are possible in a sixth-degree polynomial function?

Mathematics
2 answers:
alexandr402 [8]2 years ago
6 0

Answer:

B. 6

Step-by-step explanation:

There is one possible root for every degree, so, for example, with a third-degree polynomial function, there would be 3 possible unique roots.

Mnenie [13.5K]2 years ago
4 0

Answer: 6

Step-by-step explanation:

sixth-degree only has like six numbers

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gayaneshka [121]
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3 years ago
Read 2 more answers
Solve 41-9+(8×2.3)-15+(2.1×4)
dsp73
(8x2.3)= (18.4)
(2.1x4)= (8.4)
Now you should have:
41-9+18.4-15+8.4
9+18= 27
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Should have:
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3 years ago
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Sedbober [7]
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3 years ago
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