How many unique roots are possible in a sixth-degree polynomial function?
2 answers:
Answer:
B. 6
Step-by-step explanation:
There is one possible root for every degree, so, for example, with a third-degree polynomial function, there would be 3 possible unique roots.
Answer: 6
Step-by-step explanation:
sixth-degree only has like six numbers
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95$!
Step-by-step explanation:
475 x 20% = 95
Y=x^2-5, solve for x
y+5=x^2
x=√(y+5) so
f^-1(x)=√(y+5)
What Graph? There is no attachment