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lana66690 [7]
3 years ago
7

ate 1 4 A chef is writing a shopping list for a dinner party. She needs 6 ounces of meat for each guest. If there are 40 guests,

how many pounds of meat does she need to buy?​
Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

1 guest is 6 ounces

40 guests is 240 ounces

240 ounces = 15 pounds of meat

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Answer:

(a) The sample size required is 43.

(b) The sample size required is 62.

Step-by-step explanation:

The (1 - α) % confidence interval for population mean is:

 CI=\bar x\pm z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

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(a)

The information provided is:

<em>σ</em> = 4 minutes

MOE = 72 seconds = 1.2 minutes

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

 z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a z-table.

Compute the sample size required as follows:

 MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma}{MOE} ]^{2}

          =[\frac{1.96\times 4}{1.2}]^{2}\\\\=42.684\\\\\approx 43

Thus, the sample size required is 43.

(b)

The information provided is:

<em>σ</em> = 4 minutes

MOE = 1 minute

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

 z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a z-table.

Compute the sample size required as follows:

 MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma}{MOE} ]^{2}

          =[\frac{1.96\times 4}{1}]^{2}\\\\=61.4656\\\\\approx 62

Thus, the sample size required is 62.

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