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Radda [10]
3 years ago
14

4x=3x+5 need help with this problem!

Mathematics
2 answers:
MAVERICK [17]3 years ago
7 0

Answer:

it's 5

Subtract

3

3x

3x

from both sides of the equation

4

=

3

+

5

4x=3x+5

4x=3x+5

4

−

3

=

3

combine the like terms 4

−

3

=

3

+

5

−

3

}{-3x}}=3x+5-3x

4x−3x=3x+5−3x

1

=

3

+

5

−

3

+

5

−

3

MAXImum [283]3 years ago
5 0

Answer:

its isssssssss x=5

Step-by-step explanation:

.......

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makkiz [27]
72 / 3 = 24
So the answer would be 24 hours
3 0
2 years ago
Please help with all, I’ll mark brainliest as long as you tell me how you got that answer.
Mumz [18]

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7 0
3 years ago
How many integers between 10 and 500 begin and end in 3?
hodyreva [135]

If from 0 - 10 there is 1 number ending in 3 (3) we'll aplly the same logic to 500.

Between 0-10 there is 3. Between 10 - 20 there is 13. Between 20-30 there is 23. Between 30-40 there is 33, etc.


If we divide 500 into 10 we get 50:

500 / 10 = 50


That means there are 50 groups of 10 in the number 500. If we know that every 10 numbers has 1 ending in 3, we multiply 1 by 50:

1 x 50 = 50

So, our conclusion is, that there are 50 numbers ending in 3 between 10 and 500.


Hope it helped,


BioTeacher101

5 0
2 years ago
Can someone please help me
Viefleur [7K]
You could try finding the answer key

8 0
3 years ago
Read 2 more answers
An integer minus 5 times its reciprocal is<br> 76<br> 9<br> What is the integer?
GaryK [48]

Answer: The only one of these that's an integer is 9.

Explanation: Let X be the integer. Then

X - 3/X = 26/3. Multiplying by 3X on both sides:

3X^2 - 9 = 26X

3X^2 - 26X - 9 = 0

X = (26 +/- SQRT(26^2-(4*(-27))))/6 = (26 +/- 28) / 6,

so the two solutions for X are 1/3 and 54/6 = 9.
4 0
3 years ago
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