Shaded area = area of the hexagon – area of the pentagon + area of the square – area of the equilateral triangle. This can be obtained by finding each shaded area and then adding them.
<h3>Find the expression for the area of the shaded regions:</h3>
From the question we can say that the Hexagon has three shapes inside it,
Also it is given that,
An equilateral triangle is shown inside a square inside a regular pentagon inside a regular hexagon.
From this we know that equilateral triangle is the smallest, then square, then regular pentagon and then a regular hexagon.
A pentagon is shown inside a regular hexagon.
- Area of first shaded region = Area of the hexagon - Area of pentagon
An equilateral triangle is shown inside a square.
- Area of second shaded region = Area of the square - Area of equilateral triangle
The expression for total shaded region would be written as,
Shaded area = Area of first shaded region + Area of second shaded region
Hence,
⇒ Shaded area = area of the hexagon – area of the pentagon + area of the square – area of the equilateral triangle.
Learn more about area of a shape here:
brainly.com/question/16501078
#SPJ1
Change 4.2 kilometers to meters, which is 4200 meters, then add that to 325, so 4525 :)
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
The answer is 10.6 oz.
2.65 / 0.25 = 10.6
Hope this helps! If so, please mark brainliest!
Sent a picture of the solution to the problem (s).