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Anuta_ua [19.1K]
3 years ago
11

What is the hydroxide ion concentration of a solution with a pH of 4?

Chemistry
1 answer:
sashaice [31]3 years ago
8 0

Answer:

Jules

Explanation:

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How many grams of NaOH are needed to make 250mL of a 0.1M NaOH solution?
Sloan [31]

Answer:

To make 250 ml of 0.1 M NaOH, you dissolve 1 gram NaOH in enough water to make a final volume of 250 mls.

Explanation:

Your welcome! :)

3 0
3 years ago
The product of the nuclear reaction in which 40Ar is subjected to neutron capture followed by alpha emission is ________. The pr
Orlov [11]

Answer:

37S

Explanation:

Radioactivity is the spontaneous emission of particles and / or electromagnetic radiation by unstable atomic nuclei leading to their disintegration.

We have two main types of radioactivity: radioactive decay and artificial transmutation.

In radioactive decay ( natural radioactivity ), a naturally occurring radioactive element like Uranium-238 disintegrates or decays into more stable isotopes with the emission of particles and/or radiation.

23892U = 23490Th + 42He

Artificial transmutation is the collision of two particles where one particle captures the other used to bombard it. There is subsequent production of isotopes similar or different from the bombarded particle. Neutrons, alpha particles ( helium nucleus ), electrons, protons can be used to bombard elements.

147N + 42He = 178O + 11P

For the above question which is artificial transmutation, the reaction equation is

4018Ar + 10n = 3716S + 42He

So, the neutron capture by Argon-40 will produce a radioisotope Sulphur-37 with the emission of an alpha particle.

5 0
3 years ago
You wish to add 5 mg/l naocl as cl2 to a solution in a disinfection test, and you have a stock solution (household bleach) that
Alecsey [184]

Answer: -

0.1 ml of bleach should be added to each liter of test solution.

Explanation:-

Let the volume of bleach to be added is B ml.

Density of stock solution = 1.0 g/ml

Mass of stock solution = Volume of stock x density of stock

                                     = B ml x 1.0 g/ml

                                     = B g

Amount of NaOCl in this stock solution = 5% of B g

                                     = \frac{5}{100} x B g

                                     = 0.05 B g

Now each test solution must be added 5 mg/l NaOCl.

Thus each liter of test solution must have 5 mg.

Thus 0.05 B g = 5 mg

                        = 0.005 g

B = \frac{0.005}{0.05}

  = 0.1

Thus 0.1 ml of bleach should be added to each liter of test solution.

4 0
3 years ago
Let's just say I want to get my mixture to a certain pH but I add too much water to my solution. Can I just add the same volume
Dafna11 [192]

Answer:

You can

Explanation:

The concentration doesn't change when its equals out.

4 0
3 years ago
Sodium hydroxide, NaOH, reacts with sulfuric acid, H,SO,, in a neutralization reaction to
RSB [31]

Answer:

10.6 grams is approximately 0.10 moles. So you would need about 0.10 moles of sulfuric acid. That converts to about 9.80 grams.

Explanation:

hi girl i also wrote this in my test today so maube i hope it is correct.

mark me as brainliest if it helped you

7 0
3 years ago
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