Question

Find the trig ratio. Reduce to lowest terms. 6 А 8 [?] sin A US

Answer 1

Answer:

$\frac{3}{5}$

Step-by-step explanation:

GIVEN :-

• Measure of side opposite to ∠A (Perpendicular) = 6 units
• Measure of side adjacent to ∠A (Base) = 8 units

TO FIND :-

• sin A

FACTS TO KNOW BEFORE SOLVING :-

• $Hypotenuse = \sqrt{(Base)^2 + (Perpendicular)^2}$

• $\sin A = \frac{Side \: opposite \: to \: A}{Hypotenuse}$

PROCEDURE :-

Measure of perpendicular of triangle = 6 units

Measure base of triangle = 8 units

Measure of Hypotenuse = $\sqrt{(6)^2 + (8)^2} = \sqrt{36 + 64} = \sqrt{100} = 10 \: units$

Side opposite to ∠A = Perpendicular of triangle =  6 units

∴ sin A = $\frac{6}{10} = \frac{3}{5}$

Answer 2

Answer:

3/5 will be the reduced answer