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Rainbow [258]
3 years ago
10

A chemistry student needs 30.0 g of acetic acid for an experiment. He has available 1.2 kg of a 7.58% w/w solution of acetic aci

d in acetone.
Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Round your answer to 3 significant digits.
Chemistry
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

The mass of solution will be "395.78 g".

Explanation:

Given:

Mass of acetic acid,

= 30 g

Percentage,

= 7.58% w/w

Now,

⇒ % =\frac{Mass \ of \ acetic \ acid}{Mass \ of \ solution}\times 100

By putting the values, we get

⇒ 7.58=\frac{30}{Mass \ of \ solution}\times 100

⇒ Mass \ of \ solution=\frac{30\times 100}{7.58}

⇒                               =\frac{3000}{7.58}

⇒                               =395.78 \ g

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Water absorption can occur as soon as 5 minutes after ingestion and peaks around 20 minutes after ingestion.

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3 0
2 years ago
How many grams of aluminum are required to react with 35 mL of 2.0 M hydrochloric acid, HCl?__ HCl + __ Al --> __ AlCl3 + __
kiruha [24]

Answer:

0.6258 g

Explanation:

To determine the number grams of aluminum in the above reaction;

  • determine the number of moles of HCl
  • determine the mole ratio,
  • use the mole ratio to calculate the number of moles of aluminum.
  • use RFM of Aluminum to determine the grams required.

<u>Moles </u><u>of </u><u>HCl</u>

35 mL of 2.0 M HCl

2 moles of HCl is contained in 1000 mL

x moles of HCl is contained in 35 mL

x \: mol \:  =  \:  \frac{2 \:  \times  \: 35}{1000}  \\  = 0.07 \: moles \:

We have 0.07 moles of HCl.

<u>Mole </u><u>ratio</u>

  • Balanced equation

6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)

Hence mole ratio = 6 : 2 (HCl : Al

  • but moles of HCl is 0.07, therefore the moles of Al;

=  \frac{2}{6}  \times 0.07 \\  \:  = 0.0233333 \: moles

Therefore we have 0.0233333 moles of aluminum.

<u>Grams of </u><u>Aluminum</u>

We use the formula;

grams \:  = moles \:  \times  \: rfm

The RFM (Relative formula mass) of aluminum is 26.982g/mol.

Substitute values into the formula;

= 0.0233333 \: moles  \:  \times  \: 26.982 \:  \frac{g}{mol}  \\  = 0.625799 \: grams

The number of grams of aluminum required to react with HCl is 0.6258 g.

3 0
2 years ago
(1)List three things you know about<br> an atom? (2) What is matter created of?
kicyunya [14]

Answer:

Atoms consist of three basic particles: protons, electrons, and neutrons. The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge). The outermost regions of the atom are called electron shells and contain the electrons (negatively charged).

Explanation:

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2 years ago
if the density of copper is 8.9g/cm^3 and the Volume of the sample is 23.4 mL what would be the mass? ​
Black_prince [1.1K]

Answer:

The mass of copper = 208.26 grams.

Explanation:

Density = mass / volume

8.9 = mass / 23.4

mass = 8.9 * 23.4

= 208.26 grams.

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True...............................
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