F ` ( x ) = ( x² )` · e^(5x) + x² · ( e^(5x) )` =
= 2 x · e^(5x) + 5 e^(5x) · x² =
= x e^(5x) ( 2 + 5 x )
f `` ( x ) = ( 2 x e^(5x) + 5 x² e^(5x) ) ` =
= ( 2 x ) ˙e^(5x) + 2 x ( e^(5x) )` + ( 5 x² ) ` · e^(5x) + ( e^(5x)) ` · 5 x² =
= 2 · e^(5x) + 10 x · e^(5x) + 10 x · e^(5x) + 25 x² · e^(5x) =
= e^(5x) · ( 2 + 20 x + 25 x² )
Hope this helps tried to color code it
The simplest form is 15 dies this help
Answer:
i think 9
Step-by-step explanation:
45/5 is 9 so hope thus helps
Answer:
The cat should receive 1/5 of the can of food at each meal.
Step-by-step explanation:
Given that a cat is to receive 90 kcal of a canned food at each meal, and the food has a caloric density of 450 kcal per can, to determine what fraction of a can it should receive at each meal, the following calculation must be performed:
1 / (450/90) = X
1/5 = X
Thus, the cat should receive 1/5 of the can of food at each meal.
