Answer:
The answer will result in one significant digit.
Explanation:
1. Subtract:
12.1 - 12.004 = 0.096
2. ROund to the correct number of significant digits:
For addition and subtraction we round the sum or the difference to the least number of digits after the decimal point there are in the problem.
For example, SInce 12.1 has one number after the decimal point and 12.004 has three numbers after the decimal point, we round the answer to one number after the decimal point because 12.1 is the number in the problem which has the least amount of digits after the decimal point.
We round 0.096 to 0.1.
0.1 has one significant digit.
Iodine&chlorine contain negative charge.so they are anion.When we do electrolysis those charge go to anod&become ion.
Answer:
Nitrogen
Explanation:
It is the most abundant gas in the atmosphere.
Answer:
1.68 mol Ca(NO₃)₂
General Formulas and Concepts:
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- Compounds
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 275 g Ca(NO₃)₂
[Solve] mol Ca(NO₃)₂
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of Ca: 40.08 g/mol
[PT] Molar Mass of N: 14.01 g/mol
[PT] Molar Mass of O: 16.00 g/mol
Molar Mass of Ca(NO₃)₂: 40.08 + 2[14.01 + 3(16.00)] = 164.10 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
1.67581 mol Ca(NO₃)₂ ≈ 1.68 mol Ca(NO₃)₂
Nb, the transition metal(d) subshell will always be n-1, meaning the 3d subshell will be in row(period) 4. So if it’s 4d then it is row(period) 5, and if it has 3 valence electrons then the element is located in column V, or the third column in the transition metal section.