Question

A 216-L cylinder holds propane gas at 184.8 kPa of pressure and 127°C. How many moles of propane are in the cylinder?

Answer 1

Answer:

12 moles of propane.

Explanation:

From the question given above, the following data were obtained:

Volume (V) = 216 L

Pressure (P) = 184.8 KPa

Temperature (T) = 127 °C

Number of mole (n) =?

Next, we shall convert 127 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 127 °C

T(K) = 127 + 273

T(K) = 400 K

Finally, we shall determine the number of mole of propane gas in the container. This can be obtained as follow:

Volume (V) = 216 L

Pressure (P) = 184.8 KPa

Temperature (T) = 400 K

Gas constant (R) = 8.314 L.KPa/Kmol

Number of mole (n) =?

PV = nRT

184.8 × 216 = n × 8.314 × 400

39916.8 = n × 3325.6

Divide both side by 3325.6

n = 39916.8 / 3325.6

n = 12 moles

Thus, 12 moles of propane is present in the cylinder