Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
Answer:
Opps i am really sorry i donot know it
A. g(10)= -29
b.f(3)=16
c.h(-2)=-6
d.j(7)=23
e.h(a)=12/a
f. g(b+c)=-3b-3c+1 ...etc I'm bored
14x+7=-91
-7=-91-7
14x=-98
*14 *14
x= -1372
Answer:definition of midpoint, angle BCA is congruent to angle DCA
