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serg [7]
3 years ago
6

Emma borrows $2,500 from her bank to buy a used car. The loan has a 5.4% annual simple interest rate. If it takes Emma 9 months

to pay back the loan, how much interest will she be paying?
A. $101.25

B. $2,601.25

C. $3,715.00

D. $10,125.00
Mathematics
2 answers:
CaHeK987 [17]3 years ago
6 0

Answer:

$292.78

Step-by-step explanation:

Add the annual interest to the loan. Then divide the total by 9 to get the monthly cost.

Tatiana [17]3 years ago
5 0

Answer:

its c

Step-by-step explanation:

its c because you add 2,500 + 5.4% = 2,635 than it adds 135 to 2,500.

You multiply 135 x 9 = 1215 than you add that than that = 3715.

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The significant figures of 6.07 are 3 significant figures.
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3 years ago
What is the value of X?<br><br> 37 x X = 222
balandron [24]

Answer:

87

Step-by-step explanation:

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Easy algebra question below first correct answer gets brainliest
Alexxx [7]

Answer:

3

Step-by-step explanation:

Easy pythagorean theorum question.

The law states that "A squared plus B squared, equals C squared."

A and B are the two sides that border the 90 degree mark.

C is the hypotenuse or the longest side/diagonal.

Since we know C and A (I chose to use A because why not) we can fill in the equation with what we know

2^2 + ?^2 = \sqrt{13^{2} }

So

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Since the 13 is already squared in side of a root, it stays as 13

4 + x^2 = 13

4 - 4 + x^2 = 13 - 4

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7 0
3 years ago
How is StartRoot 11 ​classified? is it real and rational? or is it real and irrational? or its not a real number?
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5 0
3 years ago
Read 2 more answers
The average test scores for a particular test in algebra was 84 with a standard deviation of 5. What percentage of the students
Delicious77 [7]

Answer:

The percentage of the students scored higher than 89% is 15.87%

Step-by-step explanation:

we are given

The average test scores for a particular test in algebra was 84

so, mean is 84

\mu=84

a standard deviation of 5

so,

\sigma=5

we have

x=89

now, we can use z-score formula

z=\frac{x-\mu}{\sigma}

now, we can plug values

z=\frac{89-84}{5}

z=1

now, we can use calculator

and we get

p(z>1)=0.1587

So,

The percentage of the students scored higher than 89% is 15.87%

8 0
3 years ago
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