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Goryan [66]
3 years ago
12

Copper carbonate decomposes to make _____________ oxide and _____________ dioxide

Chemistry
1 answer:
nalin [4]3 years ago
5 0

Answer:

Copper carbonate decomposes to copper oxide and carbon dioxide

Explanation:

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concentrated sulfuric acid (H2SO4) has a concentration of 18.0 M. What volume of concentrated H2SO4 is needed to make 2.5 liters
olga2289 [7]

Answer:

V_1=0.139L=139mL

Explanation:

Hello!

In this case, since the dilution processes are characterized by the decrease of the original stock solution by holding the moles constant and therefore modify the volume, for the described dilution we can write:

C_1V_1=C_2V_2

Whereas we are asked to compute the volume of the original solution; thus, we can solve for it as shown below:

V_1=\frac{C_2V_2}{C_1}=\frac{1.0M*2.5L}{18.0M}\\\\V_1=0.139L=139mL

Best regards!

6 0
3 years ago
Read 2 more answers
Why are parts of Antarctica considered to be a desert?
defon
Less than 5cm of precipitation a year
3 0
3 years ago
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The value of delta for the [C_rF_6]^3- complex is 182 kJ/mol. Calculate the expected wavelength of the absorption corresponding
kirza4 [7]

Answer:  Yes the absorb in the visible range.

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

E=\frac{Nhc}{\lambda}

where,

E = energy of the wave  = 182 kJ/mol  = 182000 J/mol

N = avogadro's number =  6.023\times 10^{23}

h = plank constant = 6.6\times 10^{-34}Js^{-1}

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of the wave = ?

Putting all the values:

182000=\frac{6.023\times 10^{23}\times 6.6\times 10^{-34}\times 3\times 10^8m/s}{\lambda}

\lambda=0.65\times 10^{-6}m=650nm    (1nm=10^{-9}m)

The wavelength range for visible rays is 400 nm to 750 nm, thus the complex absorb in the visible range.

5 0
3 years ago
Write a story of your life when you were hurted by someone whom you trusted blindly...​
SOVA2 [1]

Answer:

Sis I think it happened with me but I am not able to remember if u want u can share if it happened with u

4 0
3 years ago
What is the % yield when 140.0 grams of Ethylene gas (C2H4) reacts with excess chlorine to form 280.0 grams of 1,2-Dichloro Etha
Arlecino [84]

Answer:

The % yield is 56.6 %

Explanation:

This is the reaction:

C₂H₄ + Cl₂  →  C₂H₄Cl₂

Molar mass of ethylene gas: 28 g/m

Mol = mass / molar mass

140 g / 28 g/m = 5 moles

Ratio is 1:1, so 5 moles of ethylene produce 5 moles of dichloro ethane.

Molar mass of C₂H₄Cl₂ = 98.9 g/m

Mass of C₂H₄Cl₂ produced = 98.9 g/m . 5 m → 494.5 g

% yield reaction

(280 g / 494.5 g ) . 100 = 56.6%

6 0
4 years ago
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