Equation of reaction
Hcl+NaoH-->Nacl+H2O
1:1
Using the formula CaVa/CbVb=na/nb
Ca(Concentation of acid)= 0.100M
Cb(Concentration of base)=0.200M
Va=?
VB=50.00ml
na=1
nb=1
from the formula
Va= CbVbna/Canb
Va= 0.2*50*1/0.1*1
=10/0.1=100ml
Therefore volume of acid = 100ml
Answer:
+1.03 V
Explanation:
The standard emf of the voltaic cell is the value of the standard potential of it, which is calculated by the standard reduction potential (E°).
The standard reduction potential is the potential needed for the reduction reaction happen, and it's determined by the reaction with the hydrogen cell (which has E° = 0.0V). The half-reactions of reduction of Ni⁺² and Ag⁺, are:
Ni⁺²(aq) + 2e⁻ → Ni(s) E° = -0.23 V
Ag⁺(aq) + e⁻ → Ag(s) E° = +0.80 V
The value is calculated by a spontaneous reaction, in which the cell with the greater E° is reduced (gain electrons), and the other is oxidized (loses electrons). So, Ag⁺ reduces.
emf = E°reduces - E°oxides
emf = 0.80 - (-0.23)
emf = +1.03 V
C6H12O6 +6O2 —> 6CO2 + 6H2O
Answer:
0.068 g
Explanation:
The equation that is used to determine the fraction q remaining in water of volume V₁ after n extractions of volume V₂ is:
qⁿ = (V₁/(V₁ + KV₂))ⁿ
Substituting in the values gives the fraction of caffeine left in the water phase:
q³ = (4.0mL/(4.0mL + 4.6(2.0mL))³ = 0.0278
The fraction of caffeine extracted into the methylene chloride phase is:
1 - 0.0278 = 0.972
The amount of caffeine extracted into the methylene chloride is:
(0.070g)(0.972) = 0.068 g
