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exis [7]
3 years ago
12

Which of the following compounds undergoes

Chemistry
1 answer:
uysha [10]3 years ago
7 0

Answer:

A. C2H4

Ethene

step by step explanation:

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In normal conditions, warm water "piles up" in the Western Pacific Ocean.<br><br> True<br> False
kakasveta [241]
In normal conditions, warm water does "pile up" in the" Western Pacific Ocean.
8 0
3 years ago
For each solute, identify the better solvent: water or carbon tetrachloride
Olin [163]
Do you mean which one out of water and carbon tetrachloride
if so it will be water
3 0
3 years ago
True/False: We always see the same side of the moon when we look at it in the sky
Mila [183]

Answer:

im pretty sure the answer to your question is false sorry if its wrong.

Explanation:

5 0
2 years ago
a sample of carbon dioxide contains 3.8 moles of oxygen atoms, how many moles of carbon dioxide are in the sample?
dedylja [7]
<h3>Answer:</h3>

1.9 moles

<h3>Explanation:</h3>

Carbon dioxide (CO₂) is a compound that is made up of carbon and oxygen elements.

It contains 2 moles of oxygen atoms and 1 mole of carbon atoms

Therefore;

We would say, 1 mole of CO₂ → 2 moles of Oxygen atoms + 1 mole of carbon atoms

Thus;

If a sample of CO₂ contains 3.8 moles of oxygen atoms we could use mole ratio to determine the moles of CO₂

Mole ratio of CO₂ to Oxygen is 1 : 2

Therefore;

Moles of CO₂ = 3.8 moles ÷ 2

                      = 1.9 moles

Hence, the moles of CO₂ present in a sample that would produce 3.8 moles of Oxygen atoms is 1.9 moles

6 0
3 years ago
If 5 L of butane is reacted what volume of carbon dioxide is produced ILL GIVE BRAINLIEST
Len [333]

Answer: First, here is the balanced reaction:  2C4H10  +  13O2  ===>  8CO2  +  10H2O.

This says for every mole of butane burned 4 moles of CO2 are produced, in other words a 2:1 ratio.

Next, let's determine how many moles of butane are burned.  This is obtained by

5.50 g / 58.1 g/mole  =  0.0947 moles butane.  As CO2 is produced in a 2:1 ratio, the # moles of CO2 produced is 2 x 0.0947  =  0.1894 moles CO2.

Now we need to figure out the volume.  This depends on the temperature and pressure of the CO2 which is not given, so we will assume standard conditions:  273 K and 1 atmosphere.

We now use the ideal gas law PV = nRT, or V =nRT/P, where n is the # of moles of CO2, T the absolute temperature, R the gas constant (0.082 L-atm/mole degree), and P the pressure in atmospheres ( 1 atm).

V = 0.1894 x 0.082 x 273.0 / 1  =  4.24 Liters.

Explanation:

8 0
2 years ago
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