d G = 2 (dG NOCl) - 2 (dG NO)
= 2 * 66.08 - 2 * 87.6 = -43.04 kJ /mol
dG = - 2.303 RT log K
-43.04 = - 2.303 RT log K
7.54 = log K
K = 3.42 * 10^7
Kp = k (RT)^dn
d n = 2 - 1 -2 = -1
Kp = (3.42 * 10^7) (8.314 * 298)^-1
Kp = 1.31 * 10^4
Answer:
It's false ok it's non electrolyte
Answer:
66 g of CO₂
Solution:
The Balance Chemical Reaction is as follow,
C₂H₂ + 5/2 O₂ → 2 CO₂ + H₂O
Or,
2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O ------- (1)
Step 1: Find out the limiting reagent as;
According to Equation 1,
56.1 g (2 mole) C₂H₂ reacts with = 160 g (5 moles) of O₂
So,
125 g of C₂H₂ will react with = X g of O₂
Solving for X,
X = (125 g × 160 g) ÷ 56.1 g
X = 356.5 g of O₂
It means for total combustion of Ethylene we require 356.5 g of O₂, but we are only provided with 60.0 g of O₂. Therefore, O₂ is the limiting reagent and will control the yield.
Step 2: Calculate Amount of CO₂ produced as;
According to Equation 1,
160 g (5 mole) O₂ produces = 176 g (4 moles) of CO₂
So,
60.0 g of O₂ will produce = X g of CO₂
Solving for X,
X = (60.0 g × 176 g) ÷ 160 g
X = 66 g of CO₂
Answer:
no equivalent peak, upfield between 0 and 3 ppm
Explanation:
NMR stands for nuclear magnetic resonance. It is a spectroscopic technique that is used for observing the local magnetic fields around an atomic nuclei. It is used to study the chemical, physical and biological properties of the matter.
In the context, the structures of the benzaldehyde and the benzyl alcohol are distinguished by the proton NMR. The hydrogen atom of aldehyde appears downfield between 9 and 11 ppm and also there is no equivalent peak for the alcohol.
The methylene hydrogens will only be significant upfield between the 0 and 3 ppm peak between the given structures.
The fossil could get damaged and broken into smaller pieces. That is a way it could make it difficult to determine the fossils age.
