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Alona [7]
3 years ago
8

Find the value of x.

Mathematics
1 answer:
Degger [83]3 years ago
6 0

Step-by-step explanation:

my guess is 11 for this question

You might be interested in
If f(x) =x-3 then find f^-1 (x)
Pepsi [2]

Answer:   x+3

The original function tells us to subtract 3 from the input x.

The inverse function will do the exact opposite: it adds 3 to the input x.

4 0
3 years ago
What annual rate of interest would you have to earn on an investment of $3500 to ensure receiving $273.00 interest after 1 year?
kogti [31]

To find the answer, we will have to find the percentage of $273 to $ 3500, and we can use the formula:

\frac{interest received}{investment amount} \times 100%

In this case:

273/3500 x 100%

=39/500 x 100%

=7.8%

Therefore the annual interest rate would be 7.8%.

Hope it helps!

8 0
3 years ago
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
Plsss help ASAP I DONT have timeeeee
vitfil [10]

Answer:

It will still be a frame

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
a rectangle has an area of 40cm. the dimensions of the rectangle are multiplied to form a new rectangle with an area of 160cm. b
denis-greek [22]
The first rectangle has a length of 20cm and a width of 2cm for the area to be 40cm. so, the dimensions must be multiplied by 4 to equal 160cm.
4 0
3 years ago
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