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Alona [7]
3 years ago
8

Find the value of x.

Mathematics
1 answer:
Degger [83]3 years ago
6 0

Step-by-step explanation:

my guess is 11 for this question

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Rick used 4 2/3 yards of fabric to sew 3 1/2 shirts. what is the unit rate of cloth he used in terms of yards per shirt
GarryVolchara [31]
For sewing 3 1/2 shirts, he used = 4 2/3 yards of fabric
Then, for 1 shirt, it would be: 4 2/3 / 3 1/2

Fabric for 1 shirt = 14/3 / 7/2
We can re-write it as: 14/3 * 2/7 = 4/3 yards

In short, Final answer would be 4/3 or 1 1/3 yards

Hope this helps!
7 0
4 years ago
7. Reesa's sister is a salesperson at Old Navy.
Margarita [4]

Answer: 24$

Step-by-step explanation:

3 0
3 years ago
Write each rate as a unit rate. $2 for 5 cans of soup.
Len [333]
If you would like to write each rate as a unit rate, you can do this using the following steps:

$2 ... 5 cans of a soup
$1 ... x cans of a soup = ? 

2 * x = 5 * 1
2 * x = 5
x = 5 / 2
x = 2.5 cans of a soup per $1

$2 ... 5 cans of a soup
$x = ? ... 1 can of a soup

2 * 1 = 5 * x
2 = 5 * x
x = 2 / 5 
x = $0.4 per 1 can of a soup
6 0
4 years ago
Darren wants to estimate the mean age in a population of trees. He'll sample nnn trees and build a 90\%90%90, percent confidence
Alchen [17]

Using the z-distribution, as we have the standard deviation for the population, it is found that the smallest sample size required to obtain the desired margin of error is of 77.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

The margin of error is given by:

M = z\frac{\sigma}{\sqrt{n}}

In this problem, we have that the parameters are given as follows:

M = 3, z = 1.645, \sigma = 16.

Hence, solving for n, we find the sample size.

M = z\frac{\sigma}{\sqrt{n}}

3 = 1.645\frac{16}{\sqrt{n}}

3\sqrt{n} = 1.645 \times 16

\sqrt{n} = \frac{1.645 \times 16}{3}

(\sqrt{n})^2 = \left(\frac{1.645 \times 16}{3}\right)^2

n = 76.97

Rounding up, the smallest sample size required to obtain the desired margin of error is of 77.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
2 years ago
The last answer choice is $0.08 per minute<br><br> PLEASE help I'll give 20 points
Rufina [12.5K]
I think i figured it out so it’s 0.37 :))))))))
4 0
3 years ago
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