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Gelneren [198K]
3 years ago
15

Roberto farms a tract of land that typically yields 69.6 kilograms of peas. A fertilizer manufacturer claims that its fertilizer

will produce a 60% increase in the yield. What total amount of peas should Roberto expect from this tract of land if he applies the fertilizer? If necessary, round your answer to the nearest hundredth.
Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:

Answer is 111.36 kilograms

Step-by-step explanation:

I hope it's helpful!

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Answer:

6.4

Step-by-step explanation:

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A coffee shop collected the following information regarding purchases from 110 of its customers 59 purchased coffee 39 purchased
Andrej [43]

Answer:

Let X be the number of customer purchased coffee

Let Y be the number of customer purchased donuts

Then X\cap Y is the number of customer purchased both coffee and donuts

X\cup Y  is the number of customer purchased both coffee or donuts

<em><u>The Number of customers purchased  only Coffee:</u></em>

Number of customers purchased  only donuts =n(X -Y)

n( X -Y) = n(X) - n(X \cap Y)

n(X-Y) = 59 -16

n(Y - X) = 43

<em><u>The Number of customers purchased  only donuts:</u></em>

Number of customers purchased  only donuts =n(Y -X)

n(Y - X) = n(Y) - n(X \cap Y)

n(Y - X) = 39 -16

n(Y - X) = 23

<u>The Number of customers did not purchase either of these items:</u>

Number of customers did not purchase either of these items = n(X\cup Y)^{\prime}

First lets find   n(X\cup Y)

n(X\cup Y) = n(X) +  n(Y) - n( X \cap Y)

n(X\cup Y) = 59 + 39 - 16

n(X\cup Y)  = 82

n(X\cup Y)^{\prime}  =110 -  n(X\cup Y)  = 28

5 0
4 years ago
A student takes an exam containing 18 multiple choice questions. The probability of choosing a correct answer by knowledgeable g
lawyer [7]

When you have to repeatedly take the same test, with constant probability of succeeding/failing, you have to use Bernoulli's distribution. It states that, if you take n tests with "succeeding" probability p, and you want to "succeed" k of those n times, the probability is

\displaystyle P(n,k,p) = \binom{n}{k}p^k(1-p)^{n-k}

In your case, you have n=18 (the number of tests), and p=0.3 (the probability of succeeding). We want to succeed between 8 and 12 times, which means choosing k=8,9,10,11, or 12. For example, the probability of succeeding 8 times is

\displaystyle P(18,8,0.3) = \binom{18}{8}(0.3)^8(0.7)^{10}

you can plug the different values of k to get the probabilities of succeeding 9, 10, 11 and 12 times, and your final answer will be

P = P(18,8,0.3) + P(18,9,0.3) + P(18,10,0.3) + P(18,11,0.3) + P(18,12,0.3)

3 0
3 years ago
What (-2)exponent3 (-2)exponent2
mote1985 [20]

Answer:

-32

Step-by-step explanation:

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3 years ago
Given f(x)=17x-18, find x when f(x)=33
vichka [17]
33=17x-18 add 18 both sides
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