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3 years ago

What is the product of barium + water

2 answers:

5 0

Barium reacts readily with water to form barium hydroxide, Ba(OH)2 and hydrogen gas (H2). The reaction is quicker than that of strontium (immediately above barium in the periodic table) but probably slower than that of radium (immediately below barium in the periodic table).

ivann1987 [24]3 years ago

3 0

Explanation:

Barium reacts readily with water to form barium hydroxide, Ba(OH)2 and hydrogen gas (H2).

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In the reaction C + O2 → CO2, 18 g of carbon react with oxygen to produce 72 g of carbon dioxide. What mass of oxygen would be n

melamori03 [73]

Answer:

54 g

Explanation:

Given data:

Mass of carbon = 18 g

Mass of CO₂ = 72 g

Mass of oxygen needed = ?

Solution:

Chemical reaction:

C + O₂ → CO₂

according to law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by French chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

In given photosynthesis reaction:

6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂

there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.

In a similar way,

C + O₂ → CO₂

18 g + X = 72

X = 72 -18

X = 54 g

Thus, 54 g of O₂ are required.

3 0

3 years ago

Read 2 more answers

Help please! I'd appreciate it

babymother [125]

Answer:

16.56 g

Explanation:

Mass is the production of Volume and Density.

m = V. d = 6 × 2.76 = 16.56 g

6 0

3 years ago

Can someone tell me how to solve this step by step? I got the answer but I want to know how to solve it I have a test !!!!

UNO [17]

C becuase that is the one that you would have to do becuase that is the only option

6 0

3 years ago

Answer True or False for each of the following statements. (a) The carburization surface was maintained at slightly less than 0.

fomenos

Answer:

verdadero/a

falso/b

verdadero/c

Explanation:

6 0

3 years ago

I NEED HELP PLEASE, THANKS! :)

marin [14]

Answer:

$\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}$

Explanation:

1. Calculate the moles of copper(II) hydroxide

$\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}$

2. Calculate the molecules of copper(II) hydroxide

$\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}$

6 0

3 years ago

What is the product of barium + water​

What is the product of barium + water