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oee [108]
3 years ago
9

PLZ HELP FAST :(

Mathematics
2 answers:
GaryK [48]3 years ago
8 0

Answer:

i would say it was either A or C

vazorg [7]3 years ago
4 0

Answer:

B. 3(x+2) can be rewritten as 3x+6 using the distributive property.

Step-by-step explanation:

When you distribute 3 into x and 2 you get the equation 3x+6 (3x and 3(2)) which makes the expressions equivalent.

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Calculate f(x) for the given domain values.
Maksim231197 [3]

Answer:

See explanation

Step-by-step explanation:

1. The given function is

f(x) =  - 3x

The domain values are: x=0, 2, -1, 4, -2

When x=0

f(0) =  - 3 \times 0 = 0

When x=2,

f(x) =  - 3 \times 2 =  - 6

When x=-1

f(x) =  - 3 \times  - 1  = 3

When x=4

f(4) =  - 3 \times 4 =  - 12

When x=-2

f( - 2) =  - 3 \times  - 2 = 6

2. The given function is

f(x) =  \frac{1}{3} x

When x=3,

f(3) =  \frac{1}{3}  \times 3 = 1

Similarly,

f( - 3) =  \frac{1}{3}  \times  - 3 =  - 1

f(300) =  \frac{1}{3}  \times 300 = 100

f( - 180) =  \frac{1}{3}  \times  - 180 =  - 60

f(99) =  \frac{1}{3}  \times 99 = 33

8 0
3 years ago
Combine Like Terms:<br><br> 3(p+5) - 8 + 11p
kykrilka [37]

Answer:

14p+7

Step-by-step explanation:

Distribute

3p+15-8+11p

6 0
3 years ago
Read 2 more answers
Vanessa bought a house for $268,500. She has a 30 year mortgage with a fixed rate of 6.25%. Vanessa’s monthly payments are $1,59
Genrish500 [490]

Answer:

Option a - $9,314.45

Step-by-step explanation:

Cost of the house = $268,500

Time of repayment = 30 years

Repayment is done monthly, so number of repayments = 30 X 12 = 360

Monthly Payment = $1595.85

Rate of interest per payment period = \frac{.0625}{12}

So, Present value of monthly payments = 1595.85 X  \frac{(1+\frac{.0625}{12})^{360}-1}{(1+\frac{.0625}{12})^{360}*(\frac{.0625}{12})}

= $259,185.55

So, Vanessa's down payment = $268,500 - $259,185.55 = $9,314.45

Hope it helps.

Thank you !!

8 0
3 years ago
A distribution with µ = 55 and σ = 6 is being standardized so that the new mean and standard deviation will be µ = 50 and σ = 10
Alekssandra [29.7K]

Solution:

\hbox{Let the distribution standarized is z}\\ \hbox{given:-}\mu =50\hbox{ and} \sigma =6\hbox{will become } \mu=50 \hbox{ and} \sigma =10\\\hbox{distribution standarized with value x=52 }\\\rm{so}\\\hbox{the value of score is:}\\z=\frac{x-\mu }{\sigma}\\\rm{if}\\p(x< 52)=p(z

3 0
3 years ago
Two standardized​ tests, a and​ b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×
Leona [35]
Adding (or subtracting) a constant to every data value adds (or subtracts) the same constant to measures of position such as center,percentiles, max or min.

Its shape and spread such as range, IQR, standard deviation remain unchanged.
When we multiply (or divide) all the data values by any constant, all measures of position (such as the mean, median, and percentiles) and measures of spread (such as the range, the IQR, and the standard deviation) are multiplied (or divided) by that same constant.
Part A:

The lowest score is a measure of location, so both addition and multiplying the lowest score of test B by 40 and adding 50 to the result will affect the lowest score of test A.

Thus, the lowest score of test A is given by 40(21) + 50 = 890

Therefore, the lowest score of test A is 890.



Part B:

The mean score is a measure of location, so both addition and multiplying the mean score of test B by 40 and adding 50 to the result will affect the lowest score of test A.

Thus, the mean score of test A is given by 40(29) + 50 = 1,210

Therefore, the mean score of test A is 890.



Part C:

The standard deviation is a measure of spread, so multiplying the standard deviation of test B by 40 will affect the standard deviation but adding 50 to the result will not affect the standard deviation of test A.

Thus, the standard deviation of test A is given by 40(2) = 80

Therefore, the standard deviation of test A is 80.



Part D

The Q3 score is a measure of location, so both addition and multiplying the Q3 score of test B by 40 and adding 50 to the result will affect the Q3 score of test A.

Thus, the Q3 score of test A is given by 40(28) + 50 = 1,170

Therefore, the Q3 score of test a is 1,170.



Part E:

The median score is a measure of location, so both addition and multiplying the median score of test B by 40 and adding 50 to the result will affect the median score of test A.

Thus, the median score of test A is given by 40(26) + 50 = 1,090

Therefore, the median score of test A is 1,090.



Part F:

The IQR is a measure of spread, so multiplying the IQR of test B by 40 will affect the IQR but adding 50 to the result will not affect the IQR of test A.

Thus, the IQR of test A is given by 40(6) = 240

Therefore, the IQR of test A is 240.
6 0
3 years ago
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