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3 years ago

Please help!!

Physics

1 answer:

aalyn [17]3 years ago

5 0

Answer: C. Equations were used to identify regions around the nucleus where electrons would likely be.

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What are two ways that machines make work easier?

9966 [12]

Answer: example 1: increase force applied to object. Example 2: Increase distance over which work applied. Example 3: Change direction of applied force.

Explanation:

4 0

3 years ago

When comparing and contrasting EM and mechanical waves, which is true.

GaryK [48]

Answer:

Mechanical waves- travel faster in solids & slowest in gases 2. Electromagnetic waves- travel fastest in empty space and slowest in solids.

Explanation:

6 0

4 years ago

What two factors affect projectile motion? A) distance and angle B) distance and amplitude C) initial velocity and angle D) init

maksim [4K]

Answer:

C) Initial velocity and angle

Explanation:

The path of the projectile motion is a parabolic path. The motion of a projectile motion is studied by splitting the motion into 2 mutually perpendicular components; one along the horizontal x axis and other vertical y axis.

The position of the projectile at any time $t$ is given as:

$x=ut\cos \theta\\y=ut\sin \theta - \frac{1}{2}gt^2$

Where,

$u\rightarrow \textrm{Initial velocity}\\v\rightarrow \textrm{Final velocity}\\\theta\rightarrow \textrm{Angle of projection}\\g\rightarrow \textrm{Acceleration due to gravity}$

From the above equations, we conclude that,

The projectile motion depends on two factors:

i. Initial velocity ( $u$ )

ii. Angle of projection ( $\theta$ )

Option C is correct.

4 0

3 years ago

Yellow light (600 nm) passes

hjlf

Answer:

1.66 x 10^-6 m

Explanation:

8 0

2 years ago

A grapefruit falls from a tree and hits the ground 0.64 s later.

Dmitry [639]

Answer:

Approximately $2.0\; \rm m$ , assuming that $g = 9.81 \; {\rm m \cdot s^{-2}}$ and that air resistance is negligible.

Explanation:

If air resistance is negligible, the acceleration of this grapefruit during the fall would be constantly equal to $g$ (gravitational field strength.)

Let $a$ denote the acceleration of this grapefruit.
Let $t$ denote the duration of the fall.
Let $v_{0}$ denote the initial velocity of this grapefruit (right before the fall started.)

Let $x$ denote the distance that the grapefruit travelled during the fall. The following SUVAT equation gives an expression for $x\!$ in terms of $a$ , $t$ , and $v_{0}$ :

$\begin{aligned}x &= \frac{1}{2}\, a\cdot t^{2} + v_{0}\, t\end{aligned}$ .

In this question, the grapefruit was initially on a tree. Hence, assume that the initially velocity of this grapefruit was $v_{0} = 0\; \rm m\cdot s^{-1}$ right before the fall started.

If there was no drag on the grapefruit during the fall, the acceleration of this grapefruit would be equal to the gravitational field strength: $a \approx 9.81\; \rm m\cdot s^{-2}$ .

The duration of the fall, $t$ , has also been given. Hence, the distance that the grapefruit travelled during the fall would be:

$\begin{aligned}x &= \frac{1}{2}\, a\cdot t^{2} + v_{0}\, t \\ &= \frac{1}{2} \times 9.81\; \rm m\cdot s^{-2} \times (0.64\; \rm s)^{2} + 0 \\ &\approx 2.0\; \rm m\end{aligned}$ .

7 0

3 years ago