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2 years ago

12

Calculate the GPE of a rock with a mass of 55kg on a cliff that is 27m high

1 answer:

GaryK [48]2 years ago

4 0

Answer:

<em>P=mgh</em>

<em>P=mghm=55</em>

<em>P=mghm=55g=9.8 or ~10</em>

<em>P=mghm=55g=9.8 or ~10h=27</em>

Explanation:

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3 years ago

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3 years ago

A double nozzle lying in a horizontal x-y plane discharges water into the atmosphere at a rate of 0.5 m3 /s. Assume the water sp

Kisachek [45]

Answer:

The force is $F= 46.25kN$

Explanation:

The diagram for this question is shown on the first uploaded image

At Equilibrium the summation of the of force on the vertical axis is zero

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$v_2 = \frac{R}{A_n}$

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$v_2 = \frac{0.5}{\frac{\pi}{4} * (12*\frac{1}{100} )^2 }$

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$v_1$ is the is the speed of water at the pipe which can be mathematically evaluated as

$v_1 = \frac{R}{A_p}$

substituting $0.5m^3/s$ for R and $\frac{\pi}{4}(30*\frac{1m}{100} )^2$ for $A_p$

$v_1 = \frac{0.5}{\frac{\pi}{4} * (30*\frac{1}{100} )^2 }$

$= 7.07 m/s$

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Substituting values into the equation above

$F_ysin 60^o = 1000 (0.5) (44.23 -7.07 cos 30)$

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=> $F_y sin \ 30^o =\rho Q (v_2 -v_1 sin \ 30^o)$

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3 years ago

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Cloud [144]

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