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zavuch27 [327]
2 years ago
5

Which state of matter has a define shape and definite volume

Physics
2 answers:
Katena32 [7]2 years ago
8 0
<h3>Answer:</h3><h2>Solids Only</h2><h3>Explanation:</h3>

Off all the states of matter, only solids have a defined shape, due to stronger bonds between its molecules/atoms. Unlike solids, Liquids and gasses take the shape of whatever container they are placed into. This, again, is due to weaker linkages between the atoms/molecules of gasses and liquids.

geniusboy [140]2 years ago
3 0

A solid has a definite shape and volume


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Distance is the total length covered = 2m + 3m = 5m

Displacement is his distance from original position.

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Displacement = 2m - 3m = -1m.

So his displacement  is 1m behind his original starting point.
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A large box slides across a frictionless surface with a velocity of 12 m/s and a mass of 4
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Answer= 8m/s

Because total Momentum before= total momentum after

Momentum before (p=mu)
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p=2(0)=0
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How does the density of a medium affectthe speed of a wave traveling through it
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3 years ago
What are (a) the energy of a photon corresponding to wavelength 6.0 nm, (b) the kinetic energy of an electron with de Broglie wa
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Explanation:

Given that,

Wavelength = 6.0 nm

de Broglie wavelength = 6.0 nm

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Using formula of energy

E = \dfrac{hc}{\lambda}

E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-9}}

E=3.315\times10^{-17}\ J

(b).  We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

\lambda=\dfrac{h}{\sqrt{2mE}}

E=\dfrac{h^2}{2m\lambda^2}

Put the value into the formula

E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-9})^2}

E=6.709\times10^{-21}\ J

(c). We need to calculate the energy of photon

Using formula of energy

E = \dfrac{hc}{\lambda}

E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-15}}

E=3.315\times10^{-11}\ J

(d). We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

\lambda=\dfrac{h}{\sqrt{2mE}}

E=\dfrac{h^2}{2m\lambda^2}

Put the value into the formula

E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-15})^2}

E=6.709\times10^{-9}\ J

Hence, This is the required solution.

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3 years ago
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Answer:

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