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Ksenya-84 [330]

3 years ago

12

Find the area of the quadrilateral whose vertices

1 answer:

Karolina [17]3 years ago

7 0

Answer:

How do we calculate the area of this quadrilateral using the coordinates of the four vertices? The answer is simple. We divide the quadrilateral in two triangles (using either of the diagonals), calculate the (positive value of) the areas of each triangle, and add these values to obtain the total area.

Step-by-step explanation:

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Step-by-step explanation:

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Ganezh [65]

Answer:

The given function is a nonlinear function because the degree of the function is 2 and we get same value of y for more than one values of x.

Step-by-step explanation:

The given function is

$y=2x^2-5$

To find the points which lie on the function, put difference values of x in the given function and find the values of y.

Put x= -2

$y=2(-2)^2-5=2(4)-5=8-5=3$

Put x= -1

$y=2(-1)^2-5=2(1)-5=2-5=-3$

Put x= 0

$y=2(0)^2-5=2(0)-5=-5=-5$

Put x=1

$y=2(1)^2-5=2(1)-5=2-5=-3$

Put x= 2

$y=2(2)^2-5=2(4)-5=8-5=3$

The table of values is shown below.

Plot these points on a coordinate plane and connect them by a free hand curve.

The given function is a nonlinear function because the degree of the function is 2 and we get same value of y for more than one values of x.

The graph of function is shown below.

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