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san4es73 [151]
3 years ago
14

Write a verbal problem that involves subtracting 4 liters.

Mathematics
1 answer:
Alona [7]3 years ago
8 0
A kiddy pool going over it’s limit so you have to subtract 4 liters to get to the safe level bar.
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A sequence starts 1,5,9,13,17<br> What’s the formula for the nth term of this sequence??
worty [1.4K]

This is an arithmetic sequence, since it's pattern is +4.

n1 = 1

d = 4

n = 1 + (n-1)(4) <-------------- This is the formula for the nth term of the sequence.

6 0
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Use synthetic division to determine f(-2) for the function f(x)=9x^3-18x^2-16x+32
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Answer: -80

Step-by-step explanation:

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3 years ago
-5r+8r+5 what is the anwser
Ksju [112]

Answer:

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Ines has saved $5. She doubles the amount she saves each week. Does the function have a constant difference or a constant ratio?
salantis [7]

Answer:

The function have a constant ratio

No, it does not represent an exponential function.

Step-by-step explanation:

As given,

Ines has saved $5. She doubles the amount she saves each week.

⇒ In first week she saved = $5

   In second week she saved = 2×$5 = $10

   In third week she saved = 2×$10 = 20

  In fourth week she saved = 2×$20 = 40

and so on..

∴ we get the series

5, 10, 20, 40 ,.......

If the series is given as a, b, c, d, ..... , then

The common difference is defined as d = b-a = c-b

The common ration is defined as r = \frac{b}{a} = \frac{c}{b}

Here, in the given question

The series is - 5, 10, 20, 40

This has no common difference , d =   10 - 5 (= 5 )≠ 20 - 10 (= 10)

As 5 ≠ 10

So the function does not define common difference .

Now,

This has common ratio , r =  \frac{10}{5} (=2) = \frac{20}{10}(=2)

As 2 = 2

So, the function represent common ratio

Now,

The function does not represent an exponential function because it is increased by common ratio.

7 0
3 years ago
B. A number cube is rolled once. What are the odds of rolling a 6?​
GREYUIT [131]

Answer:

If by "Number cube" you mean a die, then the odds of rolling a six are

    _

0.167 or \frac{1}{6}

8 0
3 years ago
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