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tia_tia [17]
3 years ago
7

Find all of the zeros of the polynomial function below, given that it has one zero at x=1.

Mathematics
1 answer:
babymother [125]3 years ago
3 0

Answer:

10

Step-by-step explanation:

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A bus ride for a senior citizen cost $1.25. A monthly pass costs $35.
Bond [772]

Answer:

25 or more

Step-by-step explanation:

30/1.is 24 so it would be 25 or more times for it to be a better deal

7 0
3 years ago
Help will give Brainliest .!!!!
elena55 [62]

Answer:

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Step-by-step explanation:

sorry it looks a little blurry

6 0
3 years ago
An interior automotive supplier places several electrical wires in a harness.Apull test measures the force required to pull spli
oksano4ka [1.4K]

Answer:

a) For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assumin Normal distribution

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical dsitribution

The result is on the figure attached.

b) For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

Step-by-step explanation:

For this case we have the following data:

28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4

The quantile-quantile or q-q plot is a graphical procedure in order to check the validity of a distributional assumption for a data set. We just need to calculate "the theoretically expected value for each data point based on the distribution in question".

If the values are asusted to the assumed distribution, we will see that "the points on the q-q plot will fall approximately on a straight line"

For this case our distribution assumed is normal.

Part a

For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assuming Normal distribution (0,1)

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical distribution

The result is on the figure attached.

Part b

For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

4 0
4 years ago
Help plz asap ????????????
jekas [21]

Answer:

6

hope it is ❤❤❤❤

THANK YOU.

8 0
3 years ago
Read 2 more answers
Consider -q &gt; 5. Use the addition and/or subtraction property of inequality to solve.
AleksandrR [38]

The correct answer would be -5 > q

In order to solve this using only addition and subtraction, what we need to do is change the side each term is on. This will allow us to get the variable to be a positive number.

-q > 5 ----> Subtract 5 from both sides

-5 - q > 0 -----> Add q to both sides

-5 > q

8 0
4 years ago
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