You can write the conversion factor as an equation.
.. 5 cm (map) = 2 miles
Now, you can multiply this equation by 23/5.
.. (23/5)*5 cm (map) = (23/5)*2 miles
.. 23 cm (map) = 9.2 miles
The actual distance is 9.2 miles.
Are there any dimensions given? because we need to know the length and width before we start.
Answer:
we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Step-by-step explanation:
Given data
n=29
mean of x = 49.98 mm
S = 0.14 mm
μ = 50.00 mm
Cl = 95%
to find out
Can we be 95% confident that machine calibrated properly
solution
we know from t table
t at 95% and n -1 = 29-1 = 28 is 2.048
so now
Now for 95% CI for mean is
(x - 2.048 × S/√n , x + 2.048 × S/√n )
(49.98 - 2.048 × 0.14/√29 , 49.98 + 2.048 × 0.14/√29 )
( 49.926757 , 50.033243 )
hence we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Answer:
a-it would cause too much of a tax increase
Answer:
24 miles
Step-by-step explanation:
In order to calculate Judy's estimation, we would simply have to multiply the actual distance in kilometers of the tour by the number of miles that Judy believes are in a single mile. This would give us Judy's estimation for how long the tour would be in miles.
40 km. * 0.6 miles = 24 miles
Finally, we can see that Judy's estimation would be that the tour is 24 miles long. Using Judy's believed conversion rate.
