All categories

2 years ago

Math question. Genius, please answer correctly.

Mathematics

1 answer:

yarga [219]2 years ago

3 0

Answer:

16-31 20, 18,25,28,31,23,19,27,22,25,20 11

32-47 33,42,36,41,47 5

48-65 65,52,61,50 4

Step-by-step explanation:

You might be interested in

If I put 1500 into my savings account and 180 of interest at 4% simple interest how long was my money in my bank

stealth61 [152]

10,800 I think that's the answer

6 0

2 years ago

What is an equation of the parabola with vertex at the origin and focus (0, 0.75)?

morpeh [17]

Answer:

$x^{2} =3y$

Step-by-step explanation:

Notice that the focus is a points on the vertical axis, that means the parabolla opens vertically, and has the form

$x^{2} =4py$

Because the parameter $p$ is positive and equal to 0.75. Additionally, the vertex is at the origin, that's why the equation is this simple.

Replacing the parameter value, we have

$x^{2} =4(0.75)y\\x^{2} =3y$

Therefore, the equation of a parabolla with vertex at the origin and focus at (0, 0.75) is $x^{2} =3y$ .

8 0

3 years ago

Y=-1/4x-5 and 2x+8y=56 determine if paralllel ,nethier or perpendicular

Dominik [7]

Answer:

Parallel

Step-by-step explanation:

In the slope-intercept form (y=mx +c), the coefficient of x tells us the slope of the line.

2x +8y= 56

Let's rewrite this equation into the slope-intercept form.

8y= -2x +56

Dividing both sides by 8:

$y= - \frac{2}{8} x + \frac{56}{8}$

$y = - \frac{1}{4} x + 7$

Slope= -¼

y= -¼x -5

Slope= -¼

Since both lines have the same slope, they are parallel to each other.

3 0

2 years ago

Find the value of each expression. Show your work.

Verdich [7]

Answer:

$A) (1.2)^{2} = 1.44$

$B)2^ 3+17-(3\times 4) = 13$

$C)\frac{(9)^2}{(3)^3} = 3$

Step-by-step explanation:

Here, the given expressions are:

A) $(1.2)^{2}$

Solving this, we get

$(1.2)^{2} = 1.2 \times 1.2 = 1.44$

⇒ $(1.2)^{2} = 1.44$

B) $2^ 3+17-(3\times 4)$

Now, solving this, we get

$2^ 3+17-(3\times 4) = (2 \times 2 \times2) + (17 -12)\\=8 + 5 = 13$

⇒ $2^ 3+17-(3\times 4) = 13$

C) $\frac{(9)^2}{(3)^3}$

Simplifying this, we get

$\frac{(9)^2}{(3)^3} = \frac{(9\times9)}{(3 \times 3\times3)} = 3$

⇒ $\frac{(9)^2}{(3)^3} = 3$

4 0

2 years ago

Using ƒ(x) = x + 6 and the domain { -1, 0, 1 }, find the range.

mars1129 [50]

The answer to the question

6 0

3 years ago