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3 years ago

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What is the definition of gravity in simple terms?

1 answer:

Tema [17]3 years ago

3 0

Answer:

Gravity, also called gravitation, in mechanics, the universal force of attraction acting between all matter. ... On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them. Gravity is measured by the acceleration that it gives to freely falling objects

1 : A force of attraction that tends to draw particles or bodies together.

2 : The attraction of bodies by the force of gravity toward the center of the earth.

3 : Great seriousness.

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Three displacements through a hedge maze. (b) The displacement vectors. (c) The first displacement vector and its components. (d

Vlad1618 [11]

Answer:

18.3 m , 25.4°

Explanation:

d1 = 6 m, θ1 = 40°

d2 = 8 m, θ2 = 30°

d3 = 5 m, θ3 = 0°

Write the displacements in the vector form

$d_{1}=6\left ( Cos40\widehat{i}+Sin40\widehat{j} \right )=4.6\widehat{i}+3.86\widehat{j}$

$d_{2}=8\left ( Cos30\widehat{i}+Sin30\widehat{j} \right )=6.93\widehat{i}+4\widehat{j}$

$d_{3}=5\widehat{i}$

The total displacement is given by

$\overrightarrow{d}=\overrightarrow{d_{1}}+\overrightarrow{d_{2}}+\overrightarrow{d_{3}}$

$d=\left ( 4.6+6.93+5 \right )\widehat{i}+\left ( 3.86+4 \right )\widehat{j}$

$d=16.53\widehat{i}+7.86\widehat{j}$

magnitude of resultant displacement is given by

$d ={\sqrt{16.53^{2}+7.86^{2}}}=18.3 m$

d = 18.3 m

Let θ be the angle of resultant displacement with + x axis

$tan\theta =\frac{7.86}{16.53}=0.4755$

θ = 25.4°

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3 years ago

An electric motor is connected to a battery. The current flows through brushes to a commutator ring, which is attached to an ele

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A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 4.00 m at constant speed. If the coeff

zysi [14]

Answer:

Work done is equal to 125.44 J

Explanation:

We have given mass of the student m = 80 kg

Distance moved d = 4 m

Acceleration due to gravity $g=9.8m/sec^2$

Coefficient of kinetic friction $\mu =0.4$

So normal force exerted by student $F=\mu mg=0.4\times 80\times 9.8=313.6N$

We know that work done is equal to multiplication of force and distance

So work done $W=Fd=313.6\times 0.4=125.44J$

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3 years ago

Green light (λ = 566 nm) strikes a single slit at normal incidence. Part A

VARVARA [1.3K]

Answer:

755 x 10⁻⁷ m

Explanation:

D = distance of screen

=2. m

d is width of slit = ?

wave length λ = 566 nm

Width of central maxima = 2 λD /d

= 3.00 x 10⁻² =2 λD /d

$d=\frac{2\times566\times10^{-9}\times2}{3\times10^{-2}}$

= 754.67 x 10⁻⁷ m .

= 755x 10⁻⁷ m

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