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Sati [7]
3 years ago
5

The burners on this electric stove provide _________ to the flow of electric current and electricity is then converted into ____

_____ energy.
A) resistance; heat
B) a pathway; conductive
C) resistance; mechanical
D) a pathway; electromagnetic
Physics
2 answers:
frez [133]3 years ago
6 0

A is actually the correct answer i just took the test The coiled burners on this electric stove provide resistance to the flow of electric current and electricity is converted into heat energy.

patriot [66]3 years ago
6 0

Answer: The correct option is A.

Explanation:

The electric stove converts electrical energy into heat energy. The electrical energy travels through the medium. It allows the electrons to flow.

Some substance allows electrons to flow more easily while other substance gives more resistance to the flow of electrons.

The heating element in the electric stove is made up of alloy. This alloy is nichrome. It offers resistance to the flow of electrons. Heat is directly proportional to the resistance. Then, it leads to convert the electrical energy into heat energy.

Therefore, the burners on this electric stove provide resistance to the flow of electric current and electricity is then converted into heat energy.

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A hockey ball accelerates from 0.m/s to 25m/s in 0.05 seconds what is the acceleration of the ball ?
S_A_V [24]

Answer:

500

Explanation:

25/0.05 .

I think this ?

3 0
3 years ago
A 50 Ohm resistance causes a current of 5 milliamps to flow through a circuit connected to a battery. What is the power in the c
UkoKoshka [18]

Answer:0.00125 watts

Explanation:

resistance=50 ohms

Current=5 milliamps

Current=5/1000 milliamps

Current =0.005 amps

power=(current)^2 x (resistance)

Power=(0.005)^2 x 50

Power=0.005 x 0.005 x 50

Power=0.00125 watts

8 0
3 years ago
Read 2 more answers
A weight of 30.0 N is suspended from a spring that has a force constant of 220 N/m. The system is undamped and is subjected to a
Nimfa-mama [501]

Answer:

F_0 = 393 N

Explanation:

As we know that amplitude of forced oscillation is given as

A = \frac{F_0}{ m(\omega^2 - \omega_0^2)}

here we know that natural frequency of the oscillation is given as

\omega_0 = \sqrt{\frac{k}{m}}

here mass of the object is given as

m = \frac{W}{g}

\omega_0 = \sqrt{\frac{220}{\frac{30}{9.81}}}

\omega_0 = 8.48 rad/s

angular frequency of applied force is given as

\omega = 2\pi f

\omega = 2\pi(10.5) = 65.97 rad/s

now we have

0.03 = \frac{F_0}{3.06(65.97^2 - 8.48^2)}

F_0 = 393 N

6 0
3 years ago
The x component of vector is -27.3 m and the y component is +43.6 m. (a) What is the magnitude of ? (b) What is the angle betwee
lara [203]

Answer:51.44 units

Explanation:

Given

x component of vector is -27.3\hat{i}

y component of vector is 43.6\hat{j}

so position vector is

r=-27.3\hat{i}+43.6\hat{j}

Magnitude of vector is

|r|=\sqrt{27.3^2+43.6^2}

|r|=\sqrt{2646.25}

|r|=51.44 units

Direction

tan\theta =\frac{43.6}{-27.3}=-1.597

vector is in 2nd quadrant thus

180-\theta =57.94

\theta =122.06^{\circ}

4 0
3 years ago
1. Simplify the following expression<br> 8-6/4-12+3^2
DanielleElmas [232]

Answer:

-5/2

Explanation:

8-6/4-12+3^2

8-6/4-12+9

2/4-12+9

LCM =4

(2-48+36)/4

(-46+36)/4

-10/4

-5/2

5 0
3 years ago
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