To solve this problem it is necessary to apply the concepts related to Young's Module, and find the radius that gives the ratio between the two given materials. Young's module can be defined as,
Where,
F= Force
L = Initial Length
A = Cross-sectional Area
Change in Length
Re-arrange the equation to find the change in Length we have,
If both the Force, as the Area and the initial length are considered constant, we can realize directly that the change in length is inversely proportional to Young's Module, therefore
Applying this concept to that of the two materials (Brass and Tungsten),
If the force caused 
to be stretched, the tungsten will stretch 0.25 of that ratio
Therefore the amount of stretch of Tungsten is 7.5*10^{-7}m
The coefficient of static friction is 0.222
Explanation:
In order for the car to remain in circular motion, the frictional force must be able to provide the necessary centripetal force. Therefore, the car will start skidding when the two forces are equal:
where the term on the left is the frictional force, while the term on the right is the centripetal force, and where
is the coefficient of static friction
m is the mass of the car
g is the acceleration of gravity
v is the speed of the car
r is the radius of the track
In this problem, we have:
r = 564 m
v = 35 m/s
And re-arranging the equation for , we can find the coefficient of static friction:
Learn more about friction:
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Answer:
B1. Pascal's law is a principal in fluid mechanics given by Blaise Pascal that states that a pressure change at any point in a confined incompressible fluid is transmitted throughout the fluid that the same change occur everywhere. 2 applications of Pascal's law are hydraulic lifts, hydraulic jacks, hydraulic hydraulic brakes ,hydraulic pumps. mark me as a braintalist list plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Answer:
To=20.44 °C
Explanation:
Given that
Velocity , v= 30 m/s
Temperature , T= 20°C
We know that specific heat capacity for air ,Cp=1.005 kJ/kg.K
By using energy conservation ,the stagnation temperature is given as
Now by putting the values in the above equation we get
To= 293.44 K
To= 293.44 - 273 °C
To=20.44 °C
Therefore the stagnation temperature will be 20.44 °C.
