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3 years ago

Hiiioo could someone please help me❤️

Mathematics

1 answer:

valentina_108 [34]3 years ago

6 0

Answer:

12 sides

Step-by-step explanation:

divide 360 (a polygons interior angle always add up to 360) by 30 to get 12 sides

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Divide 5a2 + 6a - 9 25a4 + 19a2 - a - 78.

xenn [34]

Final result is 5a2+6a-9

6 0

3 years ago

Carl is making a rectangular dog run. he has 36 one-yard sections of fence that he plans to use to keep his dig inside. he wants

lapo4ka [179]

From the given condition, it must be seen to it that the width must also be the lowest whole-number possible. Thus, the width should be equal to 1 yard. The given 36 is the perimeter of the run.
P = 2L + 2W
36 = 2L + 2(1)
L = 17
Thus, the longest whole-number length is equal to 17 yards.

8 0

3 years ago

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Find a particular solution to the differential equation y′′+2y′+y=2t2−t+3e−2t. y′′+2y′+y=2t2−t+3e−2t.

Jlenok [28]

$y''+2y'+y=2t^2-t+3e^{-2t}$

The characteristic equation is

$r^2+2r+1=(r+1)^2=0\implies r=-1$

so the characteristic solution is

$y_c=C_1e^{-t}+C_2te^{-t}$

For the particular solution, we can try looking for a solution of the form

$y_p=at^2+bt+c+de^{-2t}$
$\implies{y_p}'=2at+b-2de^{-2t}$
$\implies{y_p}''=2a+4de^{-2t}$

Substituting into the ODE, we have

$(2a+4de^{-2t})+2(2at+b-2de^{-2t})+(at^2+bt+c+de^{-2t})=2t^2-t+3e^{-2t}$
$at^2+(4a+b)t+(2a+2b+c)+de^{-2t}=2t^2-t+3e^{-2t}$
$\implies\begin{cases}a=2\\4a+b=-1\\2a+2b+c=0\\d=3\end{cases}\implies a=2,b=-9,c=14,d=3$

So the general solution to the ODE is

$y=y_c+y_p$
$y=C_1e^{-t}+C_2te^{-t}+2t^2-9t+14+3e^{-2t}$

4 0

3 years ago

Find the volume of the following square pyramid

yanalaym [24]

Answer:

15 cm

sana po maka tulong

7 0

3 years ago

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An online survey company wants to know if customer age is important in deciding to subscribe. The company has gathered a random

aleksley [76]

Answer:

service subscription and age are not independent

Step-by-step explanation:

The appropriate statistical test to adopt for the above problem is the Chisquare test.

The hypothesis :

H0 : service subscription and age are independent

H1 : service subscription and age are not independent

Observed values :

Under 18 18-34 35 and Over Total

Yes__ 120 __262 __237__ 619

No___ 41 ___103 __237 __381

Total 161 365 574 1000

χ² = (Observed - Expected)²/Expected

Expected Values:

99.659 __ 225.935 __ 293.406

61.341 ___ 139.065 __ 180.594

The Chisquare values :

4.15172__ 5.7569__ 10.8438

6.74518_ 9.35307 __ 17.6176

χ² = 4.15172 + 5.7569 + 10.8438 + 6.74518 + 9.35307 + 17.6176 = 54.46827

Degree of freedom = (row-1)*(column-1) = (2-1)*(3-1) = 1*2 = 2

Pvalue at df = 2 ; Pvalue = 0

α = 0.05

Pvalue < Α ; Hence, we reject H0 ; and conclude that service subscription and age are not independent

3 0

3 years ago