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Brrunno [24]
3 years ago
13

Part complete the first-order reaction, 2 n2o(g) → 2 n2(g) + o2(g), has a rate constant equal to 0.76 s-1 at 1000 k. how long wi

ll it take for the concentration of n2o to decrease to 32 % of its initial concentration?
Chemistry
1 answer:
katovenus [111]3 years ago
6 0
  The  time  taken  for  the  concentration  of N2O  to  decrease  to  32%   of  its   initial   concentration  is  calculated  as  follows
  In(A1/A0)=-Kt
A1=  final  concentration  =  32/100=0.32
A0= initial   concentration  =100/1000=1
K= constant=  0.76  per  sec

time  is  therefore  calculated  as follows
In(0.32/1)=  -0.76 t
-1.1394  =-0.76t  divide  both  sid3es  by  -0.76
t  is  therefore=  1.5  s
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as the temperature of a gas increases then what hapenns to the volume of the gas if the pressure remains the same.
Brrunno [24]

The volume increases as well.

Temperature and volume have a direct relationship which means if one were to increase, the other would to. If one were to decrease, the other would do that as well.

They practically went hand in hand.

Hope this helps!

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An artifact originally had 16 grams of​ carbon-14 present. the decay model upper a equals 16 e superscript negative 0.000121 ta=
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<u>Given:</u>

Initial amount of carbon, A₀ = 16 g

Decay model = 16exp(-0.000121t)

t = 90769076 years

<u>To determine:</u>

the amount of C-14 after 90769076 years

<u>Explanation:</u>

The radioactive decay model can be expressed as:

A = A₀exp(-kt)

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Based on the given data :

A = 16 * exp(-0.000121*90769076) = 16(0) = 0

Ans: Based on the decay model there will be no C-14 left after 90769076 years

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4 years ago
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Answer:

0.311 mmol/L

Explanation:

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4 years ago
2N2O(g) +3O2(g) 4NO2(g). Which equilibrium expression is correct?
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3 years ago
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