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dezoksy [38]
3 years ago
7

2N2O(g) +3O2(g) 4NO2(g). Which equilibrium expression is correct?

Chemistry
2 answers:
elena-14-01-66 [18.8K]3 years ago
4 0
<span>Kc = [NO2]^4 / [N2O]^2[O2]^3</span>
almond37 [142]3 years ago
4 0

d is the answer should save yall some time

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Help ASAP please. I don’t understand.
WARRIOR [948]

Answer:

a

Explanation:

4 0
3 years ago
Will magnesium and fluorine atoms most likely form an ionic bond or a covalent bond?
Andreas93 [3]

Answer:

Ionic bond

Explanation:

The magnesium atom gives up 2 electrons to form a magnesium ion, Mg2+ . The two electrons are transferred to fluorine atoms to form two fluoride ions, F–.

6 0
3 years ago
Read 2 more answers
How long will it take for a 40.0 gram sample of I-131 (half-life = 8.040 days) to decay to 1/100 its original mass? ( PLEASE WIT
masya89 [10]
Idk how long will it
4 0
3 years ago
A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at
weqwewe [10]

Answer:

22.44°C will be the final temperature of the water.

Explanation:

Heat lost by tin will be equal to heat gained by the water

-Q_1=Q_2

Mass of tin = m_1=18.5 g

Specific heat capacity of tin = c_1=0.21 J/g^oC

Initial temperature of the tin = T_1=97.38^oC

Final temperature = T_2=T

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.7 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=21.52^oC

Final temperature of water = T_2=T

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)

we get, T = 22.44°C

22.44°C will be the final temperature of the water.

5 0
3 years ago
How much of a 400g sample remains after 4 years if a radioactive isotope has a half-life of 2 years?
timama [110]

Answer:

100 g

Explanation:

From the question given above, the following data were obtained:

Original amount (N₀) = 400 g

Time (t) = 4 years

Half-life (t½) = 2 years

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Time (t) = 4 years

Half-life (t½) = 2 years

Number of half-lives (n) =?

n = t / t½

n = 4 / 2

n = 2

Thus, 2 half-lives has elapsed.

Finally, we shall determine the amount remaining of the radioactive isotope. This can be obtained as follow:

Original amount (N₀) = 400 g

Number of half-lives (n) = 2

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2² × 400

N = 1/4 × 400

N = 0.25 × 400

N = 100 g

Thus, the amount of the radioactive isotope remaing is the 100 g.

3 0
3 years ago
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