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dezoksy [38]
3 years ago
7

2N2O(g) +3O2(g) 4NO2(g). Which equilibrium expression is correct?

Chemistry
2 answers:
elena-14-01-66 [18.8K]3 years ago
4 0
<span>Kc = [NO2]^4 / [N2O]^2[O2]^3</span>
almond37 [142]3 years ago
4 0

d is the answer should save yall some time

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Data has been collected to show that at a given wavelength in a 1 cm pathlength cell, Beer's Law for the absorbance of Co2 is li
White raven [17]

Answer : The concentration of a solution with an absorbance of 0.420 is, 0.162 M

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

As per question, at constant path-length there is a direct relation between absorbance and concentration.

\frac{A_1}{A_2}=\frac{C_1}{C_2}

where,

A = absorbance of solution

C = concentration of solution

l = path length

A_1 = initial absorbance = 0.350

A_2 = final absorbance = 0.420

C_1 = initial concentration = 0.135 M

C_2 = final concentration = ?

Now put all the given value in the above relation, we get:

\frac{0.350}{0.420}=\frac{0.135}{C_2}

C_2=0.162M

Thus, the concentration of a solution with an absorbance of 0.420 is, 0.162 M

4 0
3 years ago
Consider the reaction.
gayaneshka [121]
<span>The answer is (D)-when the rate of the forward and reverse reactions are equal.</span>
6 0
4 years ago
Barium and lead both produce yellow precipitate with the chromate ion as part of their confirmation tests. if you had a sample t
UkoKoshka [18]
Barium is an element that is primarily used in fireworks because of its distinct green colour while on the other hand, lead is used in electrical industries due to its unique properties. The ions of these elements can simply be identified when its insoluble salts get precipitated by any process.
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Fluorine gas reacts violently with water to produce HF and ozone
serious [3.7K]

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c8.3 moles

Explanation:

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How many grams are in 1.23 x 1020 atoms of arsenic?
Alina [70]

Given the data from the question, the mass of arsenic that contains 1.23×10²⁰ atoms is 0.0153 g

<h3>Avogadro's hypothesis </h3>

6.02×10²³ atoms = 1 mole of arsenic

But

1 mole of arsenic = 75 g

Thus, we can say that:

6.02×10²³ atoms = 75 g of arsenic

<h3>How to determine the mass that contains 1.23×10²⁰ atoms</h3>

6.02×10²³ atoms = 75 g of arsenic

Therefore,

1.23×10²⁰ atoms = (1.23×10²⁰ × 75) / 6.02×10²³ atoms)

1.23×10²⁰ atoms = 0.0153 g of arsenic

Thus, 1.23×10²⁰ atoms is present in 0.0153 g of arsenic

Learn more about Avogadro's number:

brainly.com/question/26141731

6 0
2 years ago
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