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2 years ago

DEFG is a square. Find the measure of each of the angles,

Mathematics

1 answer:

kodGreya [7K]2 years ago

7 0

Answer:

EFG = 90°

GDH = 45°

FEG = 45°

DHG = 90°

have a great day!

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Pls help i need this asap

Zielflug [23.3K]

Answer:

Let x = # of commercials

y = # of movies

<u>System of Equations:</u>

x + y = 90

40x + 110y = 500

Step-by-step explanation:

We have to set our variables before we start solving. After setting the variables, we can set up the equations. If x = # of commercials and y = # of movies, then we can assume x + y = 90, as there have been a total of 90 commercials and movies played altogether. Then, we know that their worth is $500, so the price of all the commercials played and the price of all the movies played (which is 40x + 110y) sum to $500.

8 0

2 years ago

7. Using the distance formula, calculate how far Hector threw the ball. (4 points: 2

iragen [17]

The required distance covered is 90 units

<h3>Distance formula</h3>

The formula for calculating the distance between two points is expressed as shown:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The required coordinates missing are (0, 42.78) and (90.42.78). Substiute the coordinate into the formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$D=\sqrt{(42.78-42.78)^2+(90-0)^2}\\D=\sqrt{(0^2+(90)^2}\\D = 90 units$

Hence the required distance covered is 90 units

Learn more on distance formula here: brainly.com/question/1872885

7 0

2 years ago

Slope Find Value of Zero

NeX [460]

Answer:

(3, -6) and (7, -6)

Step-by-step explanation:

Plugging it in the slope formula we get -6+6 = 0, meaning the division will be 0. This the slope is 0

6 0

3 years ago

Write an equation for line p.

musickatia [10]

I think it’s y = -4

5 0

3 years ago

A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

tester [92]

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.$

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

4 0

3 years ago