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Anastaziya [24]
3 years ago
6

DEFG is a square. Find the measure of each of the angles,

Mathematics
1 answer:
kodGreya [7K]3 years ago
7 0

Answer:

EFG = 90°

GDH = 45°

FEG = 45°

DHG = 90°

have a great day!

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Select the correct answer.
mariarad [96]

The answer to this Question is A

What is Absolute Value Function or so called Modulus Function or Mod function?

It is a function that takes all real values as input and returns same values but +ve in nature eg if you give input as 2, output will be 2 and if you give input as -2, you will get output 2 again

Solution:

We have expression Ix-5I + 2

we know that I anything I , called as mod of anything, is always greater than or equal to zero so if we take its minimum value as 0 and we get 0 + 2 = 2

means this expression cant be less than 2 hence it will be greater than or equal to 2

because minimum value of mod is 0 and we are adding 2 to it hence overall the expression will be greater than 2 only

To learn more about Absolute Value Function click the link:

brainly.com/question/28478005

#SPJ9

4 0
2 years ago
PLEASE HELP(plssss easy math pls)
Westkost [7]
3x-12+57=90 
3x+45 =90
    -45  -45 
  3x= 45
  x=15

<MNQ= 33 because 90-57=33

Please mark as brainliest! 
Hope this helped!:))


7 0
3 years ago
Read 2 more answers
Find the value of x in each case: (See picture)
sergiy2304 [10]

Step-by-step explanation:

180-124=56°

180-56-2x-(180-6x)=0

180-56-2x-180+6x=0

-56+4x=0

4x=56

x=14°

........

2x=28

6x=84

5 0
3 years ago
Describe how to transform the graph of f into the graph of g.
Leokris [45]
We are given with two functions <span>f(x)= x^2 and g(x) = -x^2. in this case, we can plot the first equation having a y with two values -x and x. On the other hand, in the second function, when we use the same values of x, the y-value is the negative of the y-value in used in the first equation. Hence the answer is  </span><span>4)reflect the graph of f across the x axis.</span>
5 0
3 years ago
HELPPPPP
Valentin [98]

Step-by-step explanation:

How do you figure out if a relation is a function? You could set up the relation as a table of ordered pairs. Then, test to see if each element in the domain is matched with exactly one element in the range. If so, you have a function!

3 0
3 years ago
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