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Mariana [72]
3 years ago
11

Pot fi separați izotopii cu ajutorul analizei chimice?

Chemistry
1 answer:
AveGali [126]3 years ago
6 0

Answer:

pardon nut can you translate it in english

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if a gas has an initial pressure of 24,650 pa and an initial volume of 376 ml, what is the final volume if the pressure of the g
NNADVOKAT [17]

If a gas has an initial pressure of 24,650 pa and an initial volume of 376 ml, then the final volume would be 11,943.8144 ml if the pressure of the gas is changed to 775 torr assuming that the amount and the temperature of the gas remain constant.

It is given that the initial pressure P₁ is 24,650Pa and initial volumeV₁ is 376ml and the final pressureP₂ is 775 torr. We need to find the final volume of the gas. The final volume could be found using the following formula:

P₁V₁ = P₂V₂

By substituting the values, we get

24650 x 376 = 776 x V₂

9268400 = 776V₂

V₂ = 9268400/776

V₂ = 11,943.8144 ml

Therefore, the final volume of the gas would be 11,943.8144 ml

To know more about Partial pressure, click below:

brainly.com/question/14119417

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5 0
1 year ago
Why would fluorine, chlorine, and bromine be placed in the same group (the halogens) in the periodic table of elements? (1 point
inna [77]

D. They share chemical properties.

7 0
4 years ago
Significant digits are the number of digits that reflect the precision of a measurement or number.
Delvig [45]

Answer:

True

Explanation:

Significant digits are numbers that helps to present the precision of measurements calculations.

Numbers that do not contribute to the precision of a reading should not be counted as significant.

There are rules of assigning significant numbers:

  • Leading or trailing zeros are insignificant and should only be counted as a place holder.
  • All non-zero digits are significant
  • Zeroes between non-zero digits are significant.
  • Leading zeros in a decimal are significant before the number.
  • All the numbers in a scientific notation are significant.
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3 years ago
Ni4+ + _____e- LaTeX: \longrightarrow⟶ Nix+
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Kdd was he e shxiuw r thai ed
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3 years ago
When 4.5 mol al react with 11.5 mol hcl, what is the limiting reactant, and how many moles of h2 can be formed?
ahrayia [7]
1°/ . 2 Al + 6 HCl → 2 AlCl3 + 3 H2 

<span>k1 = n(Al) / 2 = 4,5 / 2 = 2,25 </span>
<span>k2 = n(HCl) / 6 = 11,5 / 6= 1,92 </span>

<span>k2 < k1 ==> HCl is the limiting reactant </span>

<span>6 mol of HCl ---> 2 mol of H2 </span>
<span>11,5 mol of HCl ---> 3,83 mol of H2 </span>
5 0
3 years ago
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